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3 years ago

According to one acid-base theory, the H2O(l) molecules act as a...

2 answers:

4 0

It depends on what the reaction is. Usually H2O is neutral. If in the reaction, it accepts proton(H+), it is base. If it donors the proton(H+), it is acid. So it based on what reaction it is.

weqwewe [10]3 years ago

4 0

Answer: both an acid and base

Explanation: By Bronsted-Lowery acid base theory: proton Donor is acid and proton Acceptor is base.

Here H2O by donating the proton acts as acid.

H2O ------> H^+ + OH^-

And by accepting the proton acts as base

H2O + H+ --------> H3O+

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The nutritional information on a cereal box shows that one serving of dry cereal has 90 calories (actually kilocalories). If one

umka2103 [35]

Answer:

90 °C

Explanation:

First, we must know the specific heat capacity of water, which is defined as the energy required to heat 1 gram of water by one degree Celsius. The specific heat capacity of water is 1 cal·g⁻¹°C⁻¹.

The equation we will use is Q = mcΔt, where Q is the heat energy, m is the mass, c is the specific heat capacity, and Δt is the temperature change. We will rearrange the equation to solve for Δt and substitute the values:

Δt = Q / (mc) = (90 kcal)(1000 cal/kcal) / (1 kg)(1000 g/kg)(1 cal·g⁻¹°C⁻¹) = 90 °C

5 0

4 years ago

A sample of copper metal has a mass of 848 grams. How many moles of copper are in the sample? 13.34 mol Cu, 13.3 mol Cu, 12.9 mo

ANTONII [103]

Answer:

$mol_{Cu}=13.34molCu$

Explanation:

Hello,

In this case, as the atomic mass of coppe is 63.546 g/mol, with the given mass with can compute the moles as shown below:

$mol_{Cu}=848gCu*\frac{1molCu}{63.546 gCu} \\\\mol_{Cu}=13.34molCu$

Best regards.

8 0

4 years ago

The balanced equation for combustion in an acetylene torch is shown below:

vichka [17]

Answer:

70mol

Explanation:

The equation of the reaction is given as:

2C₂H₂ + 5O₂ → 4CO₂ + 2H₂O

Given parameters:

Number of moles of acetylene = 35.0mol

Number of moles of oxygen in the tank = 84.0mol

Unknown:

Number of moles of CO₂ produced = 35.0mol

Solution:

From the information given about the reaction, we know that the reactant that limits this combustion process is acetylene. Oxygen is given in excess and we don't know the number of moles of this gas that was used up. We know for sure that all the moles of acetylene provided was used to furnish the burning procedure.

To determine the number of moles of CO₂ produced, we use the stoichiometric relationship between the known acetylene and the CO₂ produced from the balanced chemical equation:

From the equation:

2 moles of acetylene produced 4 moles of CO₂

∴ 35.0 mol of acetylene would produced:

$\frac{35 x 4}{2}$ = 70mol