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KengaRu [80]
4 years ago
8

When a lipid is formed, three fatty acid molecules are joined to one ________ molecule.

Chemistry
1 answer:
Alekssandra [29.7K]4 years ago
6 0
I’m almost certain that it joins a MUSCLE molecule (I put muscle in all caps so you would know the answer )
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After 62.0 min, 33.0% of a compound has decomposed. What is the half-life of this reaction assuming first-order kinetics?
nikdorinn [45]
Half life is determined using the equation expressed as:

A = Ao e^-kt

First, we need to find for the value k.

A = .67Ao = Ao e<span>^-k(33 min)
k = 0.0121

The half-life is then calculated as follows:
</span>A = .5Ao = Ao e<span>^-0.0121(t)
</span><span>t = 57.28 min

</span>
3 0
4 years ago
Please help ASAP
aev [14]

Answer:

1st one is correct, Igneous rocks are formed when molten rock cools and hardens.

5 0
3 years ago
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True or false stars will eventually burn out causing the universe become cold and dark
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Answer:

False

Explanation:

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How come there is only 3 C5H12 isomers?
liraira [26]

That's because the first and last carbon atoms cannot be branched to form an isomer . Therefore only the three middle carbon atoms can form isomers.

4 0
3 years ago
How many grams of H2O are produced when 35.0 g of NaOH reacts with 17.5 g of CO,?
zhenek [66]

Answer:

2NaOH + CO2 -> Na2CO3 + H2O

1) Find the moles of each substance

\eq n(NaOH)=\frac{35.0}{22.99+16.00+1.008\\}\  =\frac{35.0}{39.998} \ = 0.8750437522 moles\\n(CO_{2} ) = \frac{17.5}{12.01+32.00} = \frac{17.5}{44.01} = 0.3976369007 moles\\

2) Determine the limitting reagent

\\NaOH = \frac{0.8750437522}{2} = 0.4375218761\\\\

∴ Carbon dioxide is limitting as it has a smaller value.

3) multiply the limiting reagent by the mole ratio of unknown over known

n(H2O ) = 0.3976369007 × 1/2

             = 0.1988184504 moles

4) Multiply the number of moles by the molar mass of the substance.

m = 0.1988184504 × (1.008 × 2 + 16.00)

   = 0.1988184504 × 18.016

   = 3.581913202 g

Explanation:

6 0
3 years ago
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