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gtnhenbr [62]
3 years ago
5

Please help mee 11-14

Chemistry
1 answer:
Artemon [7]3 years ago
7 0

Answer:

11. A)outward

12. B) inward

13. B) opaque

14. I really don't know (sorry)

Explanation:

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A mixture of krypton and argon gas is expanded from a volume of 88.0L to a volume of 100.0L, while the pressure is held constant
Firlakuza [10]

Answer:

-3.28 × 10⁴ J

Explanation:

Step 1: Given data

  • Pressure exerted (P): 27.0 atm
  • Initial volume (Vi): 88.0 L
  • Final volume (Vf): 100.0 L

Step 2: Calculate the work (w) done by the gaseous mixture

We will use the following expression.

w = -P × ΔV = -P × (Vf - Vi)

w = -27.0 atm × (100.0 L - 88.0 L)

w = -324 atm.L

Step 3: Convert w to Joule (SI unit)

We will use the conversion factor 1 atm.L = 101.325 J.

-324 atm.L × 101.325 J/1 atm.L = -3.28 × 10⁴ J

5 0
3 years ago
A barium atom attains a stable electron configuration when it bonds with?
adell [148]
The answer is B. two chlorine atoms.
The chemical formula of the compound is BaCl2~

6 0
2 years ago
An airplane travels 2100 km at 1000km/hE. It encounters a wind and slows to 800 km/h E for the next 1300 km. What is the average
Deffense [45]

Answer:

The average velocity of the airplane for this trip is 1684.21 km/h

Explanation:

Average velocity is the rate of change of displacement with time. That is,

Average velocity = \frac{Displacement }{Change in time} = Δx / Δt = \frac{x2 - x1}{t2 - t1}

Now we will calculate the time taken by the airplane for the first motion before it encounters a wind.

From,

Velocity = \frac{Distance traveled}{Time taken}

Time = \frac{Distance traveled}{Velocity}

Therefore, Time = \frac{2100km }{1000km/h}

Time = 2.1h

This is the time taken before the airplane encounters a wind.

Hence, t1 = 2.1h

Now, For the time taken by the airplane when it encounters a wind

Also from,

Velocity = \frac{Distance traveled}{Time taken}

Time = \frac{Distance traveled}{Velocity}

Therefore, Time = \frac{1300km }{800km/h}

Time = 1.625h

Hence, t2 = 1.625h

Now, to calculate the average velocity

Average velocity = \frac{x2 - x1}{t2 - t1}

x1= 2100, x2= 1300, t1= 2.1h and t2= 1.625h

Hence, Average velocity = \frac{1300 - 2100}{1.625 - 2.1}

Average velocity = 1684.21 km/h

7 0
3 years ago
Hurry please quick summary
Nadya [2.5K]
I think that work is being done on the books because they are being moved to their proper location and they will be sorted properly rather than lying on a table. Without lifting or carrying, you could sort the books by their genre or title name on the bookshelf so it will be sorted much more efficiently.

I’m not sure if this is the answer you are looking for but I hope it helps :)
3 0
3 years ago
PLEASE HELP The arrows in the chart below represent phase transitions.
Alona [7]

1, 2, and 3

hope it helps next time upload with picture

5 0
3 years ago
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