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3 years ago

Which conclusion can be made from Gay-Lussac's law? (1 point)

1 answer:

4 0

The answer to the question <u>Which conclusion can be made from Gay-Lussac's law</u> is For a constant volume, the pressure of a gas is directly proportional to the temperature in Kelvin

Gay-Lussac's law shows the relationship between the pressure of a fixed mass of gas and its temperature in Kelvin.

It states that for a constant volume, the pressure of a gas is directly proportional to the temperature in Kelvin.

Mathematically, P ∝ T

P = kT

$\frac{P}{T} = k$

$\frac{P_{1} }{T_{1} } = \frac{P_{2} }{T_{2} }$

So, the answer to the question <u>Which conclusion can be made from Gay-Lussac's law</u> is For a constant volume, the pressure of a gas is directly proportional to the temperature in Kelvin

Learn more about Gay Lussac's law here:

brainly.com/question/24002551

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How many milligrams of MgI2 must be added to 257.7 mL of 0.087 M KI to produce a solution with [I−] = 0.1000 M?

lbvjy [14]

Answer:

The answer is 465.6 mg of MgI₂ to be added.

Explanation:

We find the mole of ion I⁻ in the final solution

C = n/V -> n = C x V = 0.2577 (L) x 0.1 (mol/L) = 0.02577 mol

But in the initial solution, there was 0.087 M KI, which can be converted into mole same as above calculation, equal to 0.02242 mol.

So we need to add an addition amount of 0.02577 - 0.02242 = 0.00335 mol of I⁻. But each molecule of MgI₂ yields two ions of I⁻, so we need to divide 0.00335 by 2 to find the mole of MgI₂, which then is 0.001675 mol.

Hence, the weight of MgI₂ must be added is

Weight of MgI₂ = 0.001675 mol x 278 g/mol = 0.4656 g = 465.6 mg

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3 years ago

The leaves of the rhubarb plant contain high concentrations of diprotic oxalic acid (hooccooh) and must be removed before the st

Andrei [34K]

First we have to find Ka1 and Ka2
pKa1 = - log Ka1 so Ka1 = 0.059
pKa2 = - log Ka2 so Ka2 = 6.46 x 10⁻⁵
Looking at the values of equilibrium constants we can see that the first one is really big compared to second one. so, the pH will be affected mainly by the first ionization of the acid.
Oxalic acid is H₂C₂O₄
H₂C₂O₄ ⇄ H⁺ + HC₂O₄⁻
0.0356 M 0 0
0.0356 - x x x
Ka1 = $\frac{[H^+][HC2O4^-]}{[H2C2O4]}$ = x² / 0.0356 - x
x = 0.025 M
pH = - log [H⁺] = - log (0.025) = 1.6

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3 years ago

When a nitrogen atom becomes an ion, the atom becomes a... A. Negative ion with a radius smaller than the radius of the atom B.

mr Goodwill [35]

Answer:

B. Negative ion with a radius larger than the radius of the atom

Explanation:

When a negative ion is formed, electrons are added to the atom. As electrons are added to the atom, the size of the electron cloud increases accordingly.

As a result of this, a negative ion is always larger than its corresponding atom. Hence, nitrogen ion must be larger than the nitrogen atom based on the facts stated above.

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Explanation:

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