Question

The initial temperature of a 1.00 liter sample of argon is 293 K. The pressure is decreased from

Answer 1

The final temperature of the Argon gas is 313.5 K.

Explanation:

Using the ideal gas equation, we can find the final temperature of the Argon gas.

$\frac{P1V1}{T1} = \frac{P2V2}{T2}$

Now we have to rearrange the equation to get T2 as,

$T2 = \frac{P2V2T1}{P1V1}$

P1 = Initial pressure = 720 mm Hg = 1 atm

P2 = Final Pressure = 360 mm Hg  = 0.5 atm

V1 = initial volume = 1 L

V2 = Final Volume = 2.14 L

T1 = Initial Temperature = 293 K

T2 = Final Temperature = ?

Now we have to plugin the values as,

T2 = $\frac{0.5 atm \times 2.14 L \times 293 K}{1 atm \times1 L}$

    = 313.5 K

So the final temperature of the Argon gas is 313.5 K.