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3 years ago

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Which best describes the relationship between the line that passes through the points (1, –6) and (3, –2) and the line that pass

es through the points (4, 8) and (6, 12)

1 answer:

Setler [38]3 years ago

8 0

Both lines are parallel, since they have the same slope of 2.

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RSTU is a parallelogram. If m TSV = 31° and m SVT = 126°, explain how you can find the measure of angle URV show all steps of yo

Juliette [100K]

Answer:

23 degrees

Step-by-Step Explanation:

SU is the transversal between the two parallel lines ST and RU

so angle SUR is equal to angle TSV=31 degrees

angle RVU is 126 degrees also because it is a vertical angle with angle SVT

angle URV is the angle being looked for in the triangle URV, and we know the two others sum to 157 degrees.

Therefore, it is 23 degrees.

7 0

2 years ago

The question is attached in the picture below. (University level)

Luba_88 [7]

Answer:

nope

Step-by-step explanation:

Apply dot product which must = 0 for orthogonality.

In this case,

-(3)(2) + (-2)(-2) + (-3)(1) + (1)(4) = -1.

4 0

3 years ago

My book is 79 pages.i have been reading 10 pages each day.theres are 9 pages left to read.how many days have I been reading the

Kitty [74]

You have been reading your book for about 7 days
7(10) pages each day + 9 left

70+ 9 = 69

6 0

3 years ago

Read 2 more answers

I'm really struggling with this question. Please help!

gavmur [86]

I got 23 u might want to check it tho

3 0

3 years ago

Differentiating a Logarithmic Function in Exercise, find the derivative of the function. See Examples 1, 2, 3, and 4.

wlad13 [49]

Answer:

$\frac{dy}{dx}=\frac{x(1-2lnx)}{x^{4}}$

Step-by-step explanation:

To solve the question we refresh our knowledge of the quotient rule.

For a function f(x) express as a ratio of another functions u(x) and v(x) i.e

$f(x)=\frac{u(x)}{v(x)}\\$ , the derivative is express as

$\frac{df(x)}{dx}=\frac{v(x)\frac{du(x)}{dx}-u(x)\frac{dv(x)}{dx}}{v(x)^{2} }$

from $y=lnx/x^{2}$

we assign u(x)=lnx and v(x)=x^2

and the derivatives

$\frac{du(x)}{dx}=\frac{1}{x}\\\frac{dv(x)}{dx}=2x\\$ .

Note the expression used in determining the derivative of the logarithm function.it was obtain from the general expression of logarithm derivative i.e $y=lnx\\\frac{dy}{dx}=\frac{1}{x}$

If we substitute values into the quotient expression we arrive at

$\frac{dy}{dx}=\frac{(x^{2}*\frac{1}{x})-(2x*lnx)}{x^{4}}\\\frac{dy}{dx}=\frac{x-2xlnx}{x^{4}}\\\frac{dy}{dx}=\frac{x(1-2lnx)}{x^{4}}$

8 0

3 years ago