Question

J(–6, 2) and K(3, 2) are the endpoints of the base of an isosceles triangle. Give the x-coordinate of the third vertex.

Answer 1

Answer:

Step-by-step explanation:

If you plot J and K in a coordinate plane, you see that the line formed is a perfectly horizontal line through y = 2.  In order for this triangle to be an isosceles, the third x-coordinate would have to be located midway through the x-coordinates of the base.  The midpoint between the x-coordinates is found by adding the 2 x-coordinates and dividing the sum by 2.  -6+\3 = -3 and -3/2 = -3/2.  So the x-coordinate is -3.2 or -1.5

Answer 2

Answer:

  -3/2

Step-by-step explanation:

The third vertex of an isosceles triangle is on the perpendicular bisector of the base. Here, the base is on the horizontal line y=2, so the perpendicular bisector will be on the vertical line with the x-value the same as the midpoint of the base.

That x-value is (-6 +3)/2 = -3/2.