Question

A 100N sack of potatoes is suspended by a rope. A person pushes sideways on the sack with a force at 40N. What is the tension in the rope.

Answer 1

The magnitude of the tension is the length of the sum of the two tension vectors. T=√(100²+40²)=1700N

Answer 2

Answer:

$T = 100 N \hat j + 40 N\hat i$

Explanation:

here we know that tension force in the rope is balancing the external force on the sack

here we know that vertical downward force due to weight of the potatoes is given as

$W = 100 N$

also we know that horizontal sideways it exert the force of 40 N

$F_x = 40 N$

so here net force that balance the tension force is given as

$F = 100 \hat j + 40 \hat i N$

so net tension force is given as above and its magnitude is given as

$T = \sqrt{100^2 + 40^2} = 107.7 N$