How much force is needed to accelerate a 66kg skier at 2m/s.2

Compare lunar and solar eclipses and answer the following questions:

xeze [42]

So lunar eclips earth between sun and moon
Solar eclips moon between sun and earth.
About the 3th.. im not sure, it depends on if you meen a total solar eclips or not... i think total is more rare then a lunar eclipse..

3 0

4 years ago

How does a multicellular organism develop

Klio2033 [76]

Answer:

A multicellular organism develops from a single cell called (the zygote)

Explanation:

This is because many different cell types, organized into tissues and organs. Development involves cell division, body axis formation, tissue and organ development, and cell differentiation

7 0

3 years ago

Three identical stars of mass M form an equilateral triangle that rotates around the triangle’s center as the stars move in a co

zheka24 [161]

Answer:

$v=\sqrt{\dfrac{2GM}{L}}$

Explanation:

M = Mass of planets

R = Radius of circle

v = Velocity

$\theta$ = Angle

The circle is inside the triangle

$cos\theta=\dfrac{\dfrac{L}{2}}{R}\\\Rightarrow R=\dfrac{L}{2cos\theta}$

The centripetal acceleration

$\dfrac{Mv^2}{R}=2\dfrac{GM^2}{L^2}cos\theta\\\Rightarrow \dfrac{Mv^2}{\dfrac{L}{2cos\theta}}=2\dfrac{GM^2}{L^2}cos\theta\\\Rightarrow \dfrac{Mv^22cos\theta}{L}=2\dfrac{GM^2}{L^2}cos\theta\\\Rightarrow v^2=\dfrac{2GM}{L}\\\Rightarrow v=\sqrt{\dfrac{2GM}{L}}$

The speed of the stars is $v=\sqrt{\dfrac{2GM}{L}}$

5 0

4 years ago

A 1200 kg car moves due north with a speed of 15m/s. An identical car moves due east with the same speed of 15m/s what are the d

Inga [223]

a.

The direction of the total momentum is 45°

The momentum of the first car is given by p = mv where m = mass of car = 1200 kg and v = velocity of car = 15 m/sj (since it moves due north).

So, p = mv

= 1200 kg × (15 m/s)j

= (18000 kgm/s)j

Also, the momentum of the identical car, p' = mv' where m = mass of car = 1200 kg and v' = velocity of car = (15 m/s)i (since it moves due east).

So, p' = mv'

= 1200 kg × (15 m/s)i

= (18000 kgm/s)i

So, the total momentum of the system P = p + p'

= (18000 kgm/s)j + (18000 kgm/s)i

= (18000 kgm/s)i + (18000 kgm/s)j

The direction of the total momentum of the system P is gotten from

tanФ = p'/p

= 18000 kgm/s ÷ 18000 kgm/s

= 1

Ф = tan⁻¹(1)

= 45°

The direction of the total momentum is 45°

b.

The magnitude of the total momentum of the system is 25455.84 kgm/s

The magnitude of the total momentum of the system P = √(p'² + p²)

= √[(18000 kgm/s)² + (18000 kgm/s)²]

= (18000 kgm/s)√(1 + 1)

= (18000 kgm/s)√2

= 25455.84 kgm/s

The magnitude of the total momentum of the system is 25455.84 kgm/s

Learn more about total momentum here:

brainly.com/question/25635296

6 0

3 years ago

what amount of heat is removed to lower the temperature of 80 grams of water from 75°C to 45°C? the specific heat of liquid wate

Slav-nsk [51]

Answer: option A.

Explanation:

Q= heat removed from the water

m= mass of the water = 80 grams

c = heat capacity of water= 4.18 J/g°C

Q = -10,032 joules -10,000 Joules

Negative sign indicates that heat was removed from the water

3 0

2 years ago

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