Heat absorbed to raise the temperature is given by
here
m = mass
c = 7.11 J/g C
Q = 138 KJ
Now by using the above formula we will have
So the amount of the substance will be 3.88 kg
Consider that 168.0 J of work is done on a system and 305.6 J of heat is extracted from the system. In the sense of the first la
1 answer:
To solve this problem we must resort to the Work Theorem, internal energy and Heat transfer. Summarized in the first law of thermodynamics.
Where,
Q = Heat
U = Internal Energy
By reference system and nomenclature we know that the work done ON the system is taken negative and the heat extracted is also considered negative, therefore
Work is done ON the system
Heat is extracted FROM the system
Therefore the value of the Work done on the system is -158.0J
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Answer
given,
x(t) = A t + B t²
A = -4.1 m/s
B = 5.4 m/s²
a) velocity of the particle is equal to the differentiation of Position w.r.t. time
the above equation gives the function of velocity.
b) time at which velocity of particle is zero
v = -4.1 + 10.8 t
inserting v = 0 and calculating v
0 = -4.1 + 10.8 t
10.8 t = 4.1
t = 0.38 s
time at which velocity is zero is equal to 0.38 s.