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Ugo [173]
3 years ago
8

Displacement can be zero but distance can't. explain this statement with example.​

Physics
1 answer:
harkovskaia [24]3 years ago
5 0

Answer:

1}can displacement be zero even when distance is not zero? Give example.  

2}how can you get speed of an object from its distance time graph ?

3}how can you get distance of an object from its speed time graph ?

4}can a body has zero velocity and still acceleration? give example .

5}is it possible in straight line motion of particle having zero speed and a non zero velocity? explain .

Explanation:

Hi friend,1).yes,displacement can be zero even when distance is not zeroexample :- when a body travels in circular path , after covering a circle the distance cannot be zero,but its displacement is zero..2).by finding the slope of distance time graph,we can find the speed of the body.3).by finding the integrating of speed time graph ,we can find the distance.4).yes,a body can have zero velocity and still acceleration.example- in vertically upward projected body,at its highest point,the velocity becomes zero but still acceleration due to gravity acts on it 5).no its not possible ..when the speed is zero..its velocity will be zero

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juin [17]

Answer:

The final velocity after the collision is 0.27 m/s.    

Explanation:

Given that,

Mass of tiger, m = 0.195 kg

Initial speed of tiger model, v = 0.75 m/s

Mass of another clay model, m' = 0.335 kg

Initially, second model is at rest, v' = 0

We need to find the final velocity after the collision. It is a case of inelastic collision. Using the conservation of linear momentum as :

mv+m'v'=(m+m')V\\\\V=\dfrac{mv+m'v'}{(m+m')}\\\\V=\dfrac{0.195\times 0.75}{(0.195 +0.335 )}\\\\V=0.27\ m/s

So, the final velocity after the collision is 0.27 m/s.    

6 0
4 years ago
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3 years ago
A 500 g model rocket is on a cart that is rolling to the right at a speed of 3.0 m/s. The rocket engine, when it is fired, exert
liberstina [14]

Answer:

x = 7.62 m

Explanation:

First we need to calculate the weight of the rocket:

W  = mg

we will use the gravity as 9.8 m/s². We have the mass (500 g or 0.5 kg) so the weight is:  

W  = 0.5 * 9.8 = 4.9 N

We know that the rocket exerts a force of 8 N. And from that force, we also know that the Weight is exerting a force of 4.9. From here, we can calculate the acceleration of the rocket:

F - W = m*a

a = F - W/m

Solving for a:

a = (8 - 4.9) / 0.5

a = 6.2 m/s²

As the rocket is accelerating in an upward direction, we can calculate the distance it reached, assuming that the innitial speed of the rocket is 0. so, using the following expression we will calculate the time which the rocket took to blast off:            

y = vo*t + 1/2 at²

y = 1/2at²

Solving for t:

t = √2y/a

t = √2 * 20 / 6.2

t = √6.45 = 2.54 s

Now that we have the time, we can calculate the horizontal distance:

x = V*t

Solving for x:

x = 3 * 2.54 = 7.62 m            

4 0
4 years ago
With no friction, you can use the relationship between potential and kinetic energy to predict the speed of the car at the botto
Dvinal [7]

The speed of the car at the bottom of the hill is obtained as, v = \sqrt{2gh}

According the principle of conservation of energy, the total potential energy of the car will be converted to maximum kinetic energy when the car is at the bottom of the hill.

K.E = P.E\\\\\frac{1}{2} mv^2 = mgh\\\\v^2 = 2gh\\\\v= \sqrt{2gh}

where;

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Thus, the speed of the car at the bottom of the hill is obtained as, v = \sqrt{2gh}

Learn more about conservation mechanical energy here: brainly.com/question/332163

3 0
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mixas84 [53]

Answer:

D

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Because neap and spring tides happen twice a month during new moon and full moon .It occurs twice in a month which is 14 days

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