3 years ago

Formation of our solar system.

Physics

1 answer:

lions [1.4K]3 years ago

6 0

Answer:

are you asking how the planets are arranged

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When placed 1.18 m apart, the force each exerts on the other is 11.2 N and is repulsive. What is the charge on each

aleksandr82 [10.1K]

Answer:

$q=41.62\ \mu C$

Explanation:

Given that,

Force between two objects, F = 11.2 N

Distance between objects, d = 1.18 m

We need to find the charge on each objects. The force between charges is as follows :

$F=\dfrac{kq^2}{r^2}\\\\q=\sqrt{\dfrac{Fr^2}{k}} \\\\q=\sqrt{\dfrac{11.2\times (1.18)^2}{9\times 10^9}} \\\\q=41.62\ \mu C$

So, the charge on each sphere is $41.62\ \mu C$ .

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3 years ago

Digital thermometers often make use of thermistors, a type of resistor with resistance that varies with temperature more than st

Nezavi [6.7K]

Answer:

The temperature coefficient of resistivity for a linear thermistor is $1.38\times10^{-3}^{\circ}C^{-1}$

Explanation:

Given that,

Initial temperature = 0.00°C

Resistance = 75.0 Ω

Final temperature = 525°C

Resistance = 275 Ω

We need to calculate the temperature coefficient of resistivity for a linear thermistor

Using formula for a linear thermistor

$R=R_{0}(1+\alpha\Delta T)$

$R=R_{0}+R_{0}\alpha\Delta T$

$\alpha=\dfrac{R-R_{0}}{R_{0}\Delta T}$

Put the value into the formula

$\alpha=\dfrac{275-75}{275\times(525-0)}$

$\alpha=1.38\times10^{-3}^{\circ}C^{-1}$

Hence, The temperature coefficient of resistivity for a linear thermistor is $1.38\times10^{-3}^{\circ}C^{-1}$

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3 years ago

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The nature-nurture question asks whether: A.a person's genes or upbringing are more important. B.children should be nurtured or

torisob [31]

The nature-nurture question asks whether "<span>a person's genes or upbringing are more important." [ Option A ]

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4 years ago

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Controlled variables

PilotLPTM [1.2K]

Answer:

A control variable in scientific experimentation is an experimental element which is constant and unchanged throughout the course of the investigation.

Explanation:

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3 years ago

An aluminum rod 17.400 cm long at 20°C is heated to 100°C. What is its new length? Aluminum has a linear expansion coefficient o

NISA [10]

Answer:

the new length is 17.435cm

Explanation:

the new length is 17.435cm

pls give brainliest

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3 years ago