P.E = mgh where
m = mass in kilograms
g = acceleration due to gravity ≈ 9.8m/s^2
h = height in meters
P.E = 10 x 9.8 x 5
P.E = 490 J
I don't know why the answer is D , because I can't see the list of choices.
The only way to get 8.0 Amps is by making a serious mistake.
The current in the second picture is 4.0 Amps.
If the resistors are identical, then the effective resistance of
two resistors in parallel is 1/2 the resistance of each one.
The resistance in the second picture is 1/2 the resistance
in the first picture.
Current = (voltage) / (resistance)
Cutting the resistance in half causes the current to double.
If the current was 2.0 Amps in the first picture, it's 4.0 Amps
in the second picture.
Answer:
There is no friction between the card and the cup.
Explanation:
Answer:
The weight of the landing craft in the vicinity of Callisto's surface is 3480 N.
Explanation:
The engine of the craft provides an upward thrust of
so that the space craft descends at a constant speed.
This implies that the net force on the space craft is zero.
The upward thrust will be equal to the downward gravitational pull by Callisto.
So the weight of the craft near the vicinity will be 3480 N.
Answer:
Acceleration = 1.428m/s2
Tension = 102.85N
Explanation:
The detailed solution is attached