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Vladimir [108]
3 years ago
6

Volume (mL) Mass (g)

Physics
2 answers:
Crank3 years ago
4 0

Answer:

A. 1.11[mL/g]

Explanation:

We have to remember the expression to calculate the density, which says it's the relationship between mass and volume.

We can calculate the different densities for each of the samples.

density1 = m/V = 200/180 = 1.11[mL/g]

density2 = m/V = 300/270 = 1.11[mL/g]

density3 = m/V = 400/270 = 1.11[mL/g]

According to the initial data, we can determine that the density corresponds to 1.11 [mL/g]

Effectus [21]3 years ago
4 0

Answer:

1.1 g ml

Explanation:

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Answer:

 N = 23.4 N

Explanation:

After reading that long sentence, let's solve the question

The contact force is the so-called normal in this case we can find it by writing the translational equilibrium equation for the y axis

            N - w₁ -w₂ =

            N = m₁ g + m₂ g

            N = g (m₁ + m₂)

let's calculate

            N = 9.8 (0.760 + 1.630)

            N = 23.4 N

This is the force of the support of the two blocks on the surface.

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What do we call a collection of matter that does not interact with anything
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A cannon ball is shot horizontally off a 37.0 m cliff and lands a distance of 18.5 m
4vir4ik [10]

Answer:

vₓ = 6.73 m/s

Explanation:

  • Assuming no other external influences than gravity, in the horizontal direction (which we make to coincide with the x- axis) , speed is constant, so, applying the definition of average velocity, we can write the following equation:

       v_{x} = \frac{\Delta x}{\Delta t} (1)

  • Now, in the vertical direction (coincident with the y- axis) , as both movements are independent each other, initial velocity is zero, so we can write the following equation for the vertical displacement:

       \Delta h = \frac{1}{2} * g * t^{2} (2)

  • where Δh = -37.0 m , g = -9.8 m/s2
  • Solving (2) for t, we get:

       t = \sqrt{\frac{2*\Delta h}{g} } =\sqrt{\frac{2*37.0m}{9.8m/s2}} = 2.75 s (3)    

  • Taking t₀ = 0, ⇒ Δt = t
  • Replacing (3) in (1), we get:

       v_{x} = \frac{\Delta x}{\Delta t} = \frac{x}{t}  = \frac{18.5m}{2.75s} = 6.73 m/s

  • As the horizontal velocity is constant, the initial horizontal velocity is just the average one, i.e., 6.73 m/s.
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