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Vladimir [108]
2 years ago
6

Volume (mL) Mass (g)

Physics
2 answers:
Crank2 years ago
4 0

Answer:

A. 1.11[mL/g]

Explanation:

We have to remember the expression to calculate the density, which says it's the relationship between mass and volume.

We can calculate the different densities for each of the samples.

density1 = m/V = 200/180 = 1.11[mL/g]

density2 = m/V = 300/270 = 1.11[mL/g]

density3 = m/V = 400/270 = 1.11[mL/g]

According to the initial data, we can determine that the density corresponds to 1.11 [mL/g]

Effectus [21]2 years ago
4 0

Answer:

1.1 g ml

Explanation:

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A 65-kg ice skater stands facing a wall with his arms bent and then pushes away from the wall by straightening his arms. At the
Marrrta [24]

Our values can be defined like this,

m = 65kg

v = 3.5m / s

d = 0.55m

The problem can be solved for part A, through the Work Theorem that says the following,

W = \Delta KE

Where

KE = Kinetic energy,

Given things like that and replacing we have that the work is given by

W = Fd

and kinetic energy by

\frac {1} {2} mv ^ 2

So,

Fd = \frac {1} {2} m ^ 2

Clearing F,

F = \frac {mv ^ 2} {2d}

Replacing the values

F = \frac {(65) (3.5)} {2 * 0.55}

F = 723.9N

B) The work done by the wall is zero since there was no displacement of the wall, that is d = 0.

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2 years ago
An object moving on a horizontal, frictionless surface makes a glancing collision with another object initially at rest on the s
cluponka [151]

Answer:

Momentum is always conserved, and kinetic energy may be conserved.

Explanation:

For an object moving on a horizontal, frictionless surface which makes a glancing collision with another object initially at rest on the surface, the type of collision experienced by this objects can either be elastic or an inelastic collision depending on whether the object sticks together after collision or separates and move with a common velocity after collision.

If the body separates and move with a common velocity after collision, the collision is elastic but if they sticks together after collision, the collision is inelastic.

Either ways the momentum of the bodies are always conserved since they will always move with a common velocity after collision but their kinetic energy may or may not be conserved after collision, it all depends whether they separates or stick together after collision and since we are not told in question whether or not they separate, we can conclude that their kinetic energy "may" be conserved.

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2 years ago
What did physicist James Joule's famous paddle wheel experiment demonstrate?
PilotLPTM [1.2K]

<u>Answer </u>

A. that the initial gravitational potential energy of the masses transformed into kinetic energy of the paddles and then to thermal energy in the water


<u>Explanation</u>

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The height form which the water fell, mass and the temperature of water was measured and used to calculate mechanical equivalent of heat.

From the choices given the best answer is A. that the initial gravitational potential energy of the masses transformed into kinetic energy of the paddles and then to thermal energy in the water.

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egoroff_w [7]
Sorry, but what is question 2?
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Answer:

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