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Romashka-Z-Leto [24]
3 years ago
14

If you help me get this Right, i will mark you as brilliance, AND rate your answer as 5 stars, and give you a thanks BUT only if

you get it right! Thank you ! :D

Mathematics
1 answer:
amid [387]3 years ago
6 0

Answer:

True

Step-by-step explanation:

Pi is 3.14159 but in shorter form 3.14

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Describe the transformation of y=-2/x
Kay [80]

Answer:

This transformation is known as a vertical stretch. This is the graph of a transformation of \begin{align*}y=x^2\end{align*}. The points are plotted from the vertex as right and left one and down one-half, right and left 2 and down two, right and left three and down four and one-half

6 0
3 years ago
Someone help pls -……
uysha [10]

Answer:

d) 35ft

e) 6 seconds

f) 250°

Step-by-step explanation:

If it makes one rotation (360°) in 36 seconds, then it turns 10° every second.

   36 secs = 360°

⇒ 1 sec = 360/36 = 10°

d)  After 9 seconds, it has turned:

9 x 10 = 90°

Therefore, it will be 15 + 20 = 35ft from the wall

e) 60° = 6 seconds

f) 25 seconds = 25 x 10 = 250°

8 0
2 years ago
A flat rectangular piece of aluminum has a perimeter of 60 inches. The
liq [111]

Answer:

8 inches

Step-by-step explanation:

Let w represent the width.

If the length is 14 inches longer than the width, it can be represented by w + 14.

Use the perimeter formula, p = 2l + 2w. Plug in 60 as the perimeter and w + 14 as l, then solve for w:

p = 2l + 2w

60 = 2(w + 14) + 2w

60 = 2w + 28 + 2w

60 = 4w + 28

32 = 4w

8 = w

So, the width is 8 inches

4 0
3 years ago
Triangle ABC is rotated 90 degrees clockwise about the origin to create triangle A'B'C'.
frozen [14]

Note: Consider we need to find the vertices of the triangle A'B'C'

Given:

Triangle ABC is rotated 90 degrees clockwise about the origin to create triangle A'B'C'.

Triangle A,B,C with vertices at A(-3, 6), B(2, 9), and C(1, 1).

To find:

The vertices of the triangle A'B'C'.

Solution:

If triangle ABC is rotated 90 degrees clockwise about the origin to create triangle A'B'C', then

(x,y)\to (y,-x)

Using this rule, we get

A(-3,6)\to A'(6,3)

B(2,9)\to B'(9,-2)

C(1,1)\to C'(1,-1)

Therefore, the vertices of A'B'C' are A'(6,3), B'(9,-2) and C'(1,-1).

7 0
3 years ago
Someone please help<br><br><br><br><br><br><br><br> give 20 points
Leokris [45]

sqrt(200) ≈ 14.14213562373095

14 = 14

14/3 ≈ 4.666666666666667

From least-to-greatest:

14/3, 14, sqrt(200)

6 0
3 years ago
Read 2 more answers
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