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Softa [21]
3 years ago
8

This problem has been solved!See the answerCommunication with submerged submarines via radio waves is difficult because seawater

is conductive and absorbs electromagnetic waves. Penetration into the ocean is greater at longer wavelengths, so the United States has radio installations that transmit at 76Hz for submarine communications.What is the approximate wavelength of those extremely low-frequency waves?500 km1000 km2000 km4000 km
Physics
1 answer:
mash [69]3 years ago
8 0

Answer:

4000 km

Explanation:

as we know velocity of electromagnetic wave is c

c = 3 * 10^8 m/s

frequency  given (f) = 76 Hz

wavelength ?

using

c =fλ

λ =   \frac{c}{f}

λ =  \frac{3 * 10^8}{76}  ≈4000 km

 so final answer λ = 4000km

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Consider two ideal gases, A and B, at the same temperature. The rms speed of the molecules of gas A is twice that ofgas B. How d
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The rms speed of the molecules of gas A is twice that of gas B. The molecular mass of A is one fourth to that of B.

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<u>Explanation:</u>

Measuring the speed of particles at a given point in time results in a large distribution of values. Some molecules can move very slowly, others very fast, and because they are still moving in different directions, the speeds may be zero. (Velocity, vector quantity that corresponds to the speed and direction of the molecule.)

To correctly estimate the average velocity, you must take the squares of the mean velocity and take the square root of this value. This is known as the root mean square (rms) velocity and is shown as follows:

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Where,

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R – Molar mass constant

T – Temperature (in Kelvin)

Given data is rms speed for gas molecule A is twice that of gas molecule B. So,

                 \left(V_{r m s}\right)_{A}=2\left(V_{r m s}\right)_{B}

Therefore, equating the molecule’s rms speed formula for both A and B,

                  \sqrt{\frac{3 R T}{M_{A}}}=2(\sqrt{\frac{3 R T}{M_{B}}})

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                 \frac{3 R T}{M_{A}}=4\left(\frac{3 R T}{M_{B}}\right)

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                 M_{A}=\frac{M_{B}}{4}

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