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kogti [31]
3 years ago
13

How do your shoe laces relate to a pulley

Physics
1 answer:
Margarita [4]3 years ago
8 0
The grommets on your shoe (Holes through which you place the lace) act as the pulley. When you tighten at the top it restricts at the bottom and compresses around your foot. 

The same can be applied to a pulley; If you have the proper set up Pulling one string causes two actions; the first being the most obvious. And the second being its effect. The Grommets of your shoe are the pulley's; while your Shoelaces are just the rope with which you operate the pulley.
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1)Light of wavelength 588.0 nm is incident on a narrow slit. The diffraction pattern is viewed on a screen 55.5 cm from the slit
Talja [164]

Answer:

These are Diffraction Grating Questions.

Q1. To determine the width of the slit in micrometers (μm), we will need to use the expression for distance along the screen from the center maximum to the nth minimum on one side:  

Given as  

y = nDλ/w                                                       Eqn 1

where  

w = width of slit  

D = distance to screen  

λ = wavelength of light  

n = order number  

Making x the subject of the formula gives,  

w = nDλ/y  

Given  

y = 0.0149 m  

D = 0.555 m  

λ = 588 x 10-9 m  

and n = 3

w = 6.6x10⁻⁵m

Hence, the width of the slit w, in micrometers (μm) = 66μm

Q2. To determine the linear distance Δx, between the ninth order maximum and the fifth order maximum on the screen

i.e we have to find the difference between distance along the screen (y₉-y₅) = Δx

Recall Eqn 1,     y = nDλ/w  

given, D = 27cm = 0.27m  

λ = 632 x 10-9 m  

w = 0.1mm = 1.0x10⁻⁴m

For the 9th order, n = 9,

y₉ = 9 x 0.27 x 632 x 10-9/ 1.0x10⁻⁴m = 0.015m

Similarly, for n = 5,

y₅ = 5x 0.27 x 632 x 10-9/ 1.0x10⁻⁴m = 0.0085m

Recall,  Δx = (y₉-y₅) = 0.015 - 0.0085 = 0.0065m

Hence, the linear distance Δx between the ninth order maximum and the fifth order maximum on the screen = 6.5mm

8 0
3 years ago
Can anyone explain<br>if knows​
Aleks [24]

Answer:

Sry I’m just trying to get my points :(

Explanation:

Better luck nest time I would help if I was smart enough but currently I’m as d u m b as a rock...

5 0
3 years ago
Read 2 more answers
A dog runs with an initial velocity of 7.5 m/s on a waxed floor. It slides to a stop in 15 seconds. What is the acceleration?
Leni [432]

Answer:

-0.5 m/s^2

Explanation:

Acceleration = change in velocity / total time

7.5 / 15 = 0.5

3 0
3 years ago
The game was played by swinging the big mallet down hard enough to cause the bell to ring. If it took a 44 newton force to ring
nata0808 [166]
I think C. 33 newtons
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A dart is inserted into a spring-loaded dart gun by pushing the spring in by a distance x. For the next loading, the spring is c
bezimeni [28]

Answer:

The second dart leaves the gun two times as faster than the first one.

Explanation:

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U_s = K_d \\ \frac{1}{2} kx^2 = \frac{1}{2}mv^2 \\ v = \sqrt{\frac{k}{m}x^2}.

Given an arbitrary x and its double, 2x, launch velocities are

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7 0
3 years ago
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