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Ivanshal [37]
3 years ago
7

A 10-kg disk-shaped flywheel of radius 9.0 cm rotates with a rotational speed of 320 rad/s. Part A Determine the rotational mome

ntum of the flywheel. Express your answer to two significant figures and include the appropriate units. Part B With what magnitude rotational speed must a 10-kg solid sphere of 9.0 cm radius rotate to have the same rotational momentum as the flywheel? Express your answer to two significant figures and include the appropriate units.
Physics
1 answer:
Leya [2.2K]3 years ago
4 0

Answer:

(A). The rotational momentum of the flywheel is 12.96 kg m²/s.

(B). The rotational speed of sphere is 400 rad/s.

Explanation:

Given that,

Mass of disk = 10 kg

Radius = 9.0 cm

Rotational speed = 320 m/s

(A). We need to calculate the rotational momentum of the flywheel.

Using formula of momentum

L=I\omega

L=\dfrac{1}{2}mr^2\omega

Put the value into the formula

L=\dfrac{1}{2}\times10\times(9.0\times10^{-2})^2\times320

L=12.96\ kg m^2/s

(B). Rotation momentum of sphere is same rotational momentum of the  flywheel

We need to calculate the magnitude of the rotational speed of sphere

Using formula of rotational momentum

L_{sphere}=L_{flywheel}

I\omega_{sphere}=I\omega_{flywheel}

\omega_{sphere}=\dfrac{I\omega_{flywheel}}{I_{sphere}}

\omega_{sphere}=\dfrac{I\omega_{flywheel}}{\dfrac{2}{5}mr^2}

Put the value into the formula

\omega_{sphere}=\dfrac{12.96}{\dfrac{2}{5}\times10\times(9.0\times10^{-2})^2}

\omega_{sphere}=400\ rad/s

Hence, (A). The rotational momentum of the flywheel is 12.96 kg m²/s.

(B). The rotational speed of sphere is 400 rad/s.

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The gravitational force is s type of force that has the ability to attract any two objects having mass. The gravitational force will be 4.16\times10^{23}.

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The gravitational force is s type of force that has the ability to attract any two objects with mass. Gravitational force tries to pull two masses towards each other.

                      F= G\frac{m_1m_2}{r^{2} }

Given,

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mass of Jupiter(m_2)= 7.79\times10^{8} kg

distance between the sun and Jupiter (r)= 1.90\times10^{27} m

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F= 4.16\times(10)^{23}   Newton

Hence the gravitational force between the sun and Jupiter will be 4.16\times10^{23}

To learn more about  gravitational force refer to the link:

brainly.com/question/24783651

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2 years ago
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A bird flew 16 km west in 5 hours , then flew 20 km east in 6 hours . What was the birds velocity?
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John weighs 200 pounds.
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In order to lift himself to the balcony, John has to do
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If he does it in 6.2 seconds, his RATE of doing work is
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1 joule of work per second would be 1 "watt".
Too bad we're not working with metric units.)

So back to our problem.

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Well, 550 foot-pounds per second is called 1 "horsepower".

So as John runs up the steps to the balcony, he's doing the work
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_______________________________________________

Oh my gosh !  Look at #26 !  There are the metric units I was talking about.

Do you need #26 ?

I'll give you the answers, but I won't go through the explanation,
because I'm doing all this for only 5 points.

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You're welcome.

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You place a light bulb 8 cm in front of a concave mirror. You then move a sheet of paper back and forth in front of the mirror.
Alika [10]

sorry - late reply...just stumbled across tis...hope u can still use it :)


By the mirror equation: 1/di + 1/do = 1/f

<span>
</span>

<span>where di = distance to image = +12cm (+ for real image)</span>


and do = distance to object = +8cm


Substitute and solve for f, the focal length

<span><span>
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</span><span>
1/f = (8 + 12) / 12 * 8 = 20/96
</span><span>
so f = 96/20 = 4.8 cm</span>
</span>
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