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sesenic [268]
3 years ago
13

nsider a common mirage formed by superheated air immediately above a roadway. A truck driver whose eyes are 2.00 m above the roa

d, where n = 1.000 293, looks forward. She perceives the illusion of a patch of water ahead on the road. The road appears wet only beyond a point on the road at which her line of sight makes an angle of 1.30° below the horizontal. Find the index of refraction of the air immediately above the road surface. (Treat this as a problem in total internal reflection. Give your an
Physics
1 answer:
Anna11 [10]3 years ago
6 0

Answer:

n_{air}  =1.0000355

Explanation:

from snells law we have following relation

n' Sin i = n_{air} Sin r


n_{air} is refractive index of air

n' -  refractive index of air below

i is angle of incidence = 90 - 1.30 = 88.70^o

r is refraction angle

plugging all value in above formula

1.000293 \times sin 88.7 = n_{air} \times sin 90

n_{air}  =1.0000355

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within ____minutes after a drink is consumed all of the alcoholic content has probably been absorbed into your body
OverLord2011 [107]

20-60minutes

Explanation:

Within 10-20minutes after a drink is consumed all of the alcoholic content has probably been absorbed into body.

Alcohol is absorbed into the body much more fast.

  • It does not undergo digestion process like food.
  • It can easily be absorbed into the blood stream.
  • Alcohol is readily absorbed and carried round into the body.
  • It doesn't get processed like food in the body where they pass through the digestive system.
  • The body sees alcohol as nutrient.
  • It carries it to the brain and other parts of the body.

learn more;

Alcohol brainly.com/question/4541397

#learnwithBrainly

3 0
3 years ago
an airplane flies at a speed of 100 m/s and starts to accelerate constantly at a rate of 50 m/s2. how fast is the plane flying a
mart [117]

Answer:

331.7m/s

Explanation:

Given parameters:

Initial velocity  = 100m/s

Acceleration  = 50m/s²

Distance  = 1km   = 1000m

Unknown:

Final velocity = ?

Solution:

To solve this problem, we have to apply the right motion equation shown below;

     v²  = u²  + 2aS

 v is the final velocity

 u is the initial velocity

 a is the acceleration

 S is the distance

 Now insert the parameters and solve;

     v² = 100² + (2 x 50 x 1000)

     v² = 110000

     v = √110000  = 331.7m/s

4 0
3 years ago
Which of the following properties must be known in order to calculate the amount of heat needed to melt 1.0 kg of ice at 0ºC?
meriva
If you're only melting ice ... turning solid ice at 0°C into liquid water at 0°C ...
then you only need to know t<span>he latent heat of fusion for water</span>. 

That's exactly what it means ... the amount of energy involved when a gram
of H₂O changes in either direction between liquid and solid, with no change
in temperature.



7 0
3 years ago
Consider a box with two gases separated by an impermeable membrane. The membrane can move back and forth, but the gases cannot p
padilas [110]

Answer:

The answer is "0.3336\ m^3"

Explanation:

Using the Promideal gas law:

P_A=P_B\\\\P_A(V_A-\eta_A b)= \eta_A RT......(1)\\\\P_B V_B=\eta_B \bar{R}T........(2)\\\\From (1) \zeta (2)\\\\  

\frac{\eta_A}{V_A-\eta_A b}=\frac{\eta B}{V B}\\\\  \frac{V A- \eta_A b}{V B}=\frac{\eta A}{\eta B }\\\\  \frac{V A-b}{V B}=\frac{1}{2}\\\\V A+V B=1\\\\V B =1- V A\\\\\frac{V A-b}{1-V A}=\frac{1}{2}\\\\2V A-2b=1-V A\\\\3 V A=1+2b\\\\V A=\frac{1+2b}{3}\\\\

      =\frac{1+2(4\times 10^{-4})}{3}\\\\=0.3336\ m^3

8 0
3 years ago
A train is approaching a town at a constant speed of 12 m/s. The town is 1.0 km distant. After 30 seconds, the conductor applies
Yuliya22 [10]

To solve this problem we will apply the linear motion kinematic equations. To determine the position in which the braking starts we will start from the definition of distance as a function of speed and time, that is

x = x_0 - vt

Here,

x_0 = Initial position

v = Velocity

t = time

Replacing we have that

x = 1000-12*30

x = 640m

Now the acceleration is given by the function,

v_f^2=v_0^2 +ax

Here,

v_f= Final velocity

v_0= Initial velocity

a = Acceleration

x = Displacement

Replacing we have that

0 = 12^2+2a(640)

a = -0.1125m/s^2

Therefore the acceleration necessary to bring the train to rest is -0.1125m/s^2

4 0
3 years ago
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