Answer:
the height (in feet) of the cliff is 121 ft
Explanation:
A stone hit the cliff with
speed, v = 88 ft/s
Acceleration, a= 32 ft/s^2
initial speed, u = 0 ft/s
height is h.
To solve this problem we will apply the linear motion kinematic equations, Equation of motion describes change in velocity, depending on the acceleration and the distance traveled
so, writing the formula of Equation of motion:
v^2 - u^2 = 2*a*h
substituting the appropriate values,
(88)^2 - 0 = 2*32* h
h=(88)^2 / 64
h= 121 ft
hence
the height (in feet) of the cliff is 121 ft
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The picture is hard to see but if you still need help message me
You said that she's losing 1.9 m/s of her speed every second.
So it'll take
(6 m/s) / (1.9 m/s²) = 3.158 seconds (rounded)
to lose all of her initial speed, and stop.
As per the given Figure attached here we know that both charges q1 and q2 will apply same force on charge q3 and hence the resultant force due to both charges will be along Y axis vertically upwards
So here we know that

now from the above equation


so both of the charges will apply 0.288 N force on q3 charge along the line joining them
now the net force due to vector sum is given by

here we know that angle is

now we have


so net force on q3 is 0.46 N vertically upwards along +Y axis