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Zinaida [17]
3 years ago
13

Need help with this probkem

Mathematics
1 answer:
aleksley [76]3 years ago
6 0

Answer:

1073iwmwiw87eu3h3u38ww

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Can someone help please? And explain it.
sineoko [7]

Answer:

2 : 6 = 14 : 42

32 : 64 = 12 : 24

Step-by-step explanation:

This is ratios.

2 : 6 = 14 : 42 is because 2 can go into 14, 7 times, so that makes it a multiple of 2. Than you just multiply the 6 by 7 that will get you to 42.

32 : 64 = 12 : 24 is because 12 is doubled on the other side to get 24, so you just double 32 and get 64.

Hope this helps!!!


3 0
3 years ago
For the following telescoping series, find a formula for the nth term of the sequence of partial sums
gtnhenbr [62]

I'm guessing the sum is supposed to be

\displaystyle\sum_{k=1}^\infty\frac{10}{(5k-1)(5k+4)}

Split the summand into partial fractions:

\dfrac1{(5k-1)(5k+4)}=\dfrac a{5k-1}+\dfrac b{5k+4}

1=a(5k+4)+b(5k-1)

If k=-\frac45, then

1=b(-4-1)\implies b=-\frac15

If k=\frac15, then

1=a(1+4)\implies a=\frac15

This means

\dfrac{10}{(5k-1)(5k+4)}=\dfrac2{5k-1}-\dfrac2{5k+4}

Consider the nth partial sum of the series:

S_n=2\left(\dfrac14-\dfrac19\right)+2\left(\dfrac19-\dfrac1{14}\right)+2\left(\dfrac1{14}-\dfrac1{19}\right)+\cdots+2\left(\dfrac1{5n-1}-\dfrac1{5n+4}\right)

The sum telescopes so that

S_n=\dfrac2{14}-\dfrac2{5n+4}

and as n\to\infty, the second term vanishes and leaves us with

\displaystyle\sum_{k=1}^\infty\frac{10}{(5k-1)(5k+4)}=\lim_{n\to\infty}S_n=\frac17

7 0
3 years ago
What is 1/4 + 1/2<br><br>A: 1/6<br>B: 2/4<br>C: 3/4<br>D: 2/4​
Strike441 [17]

Answer: \frac{3}{4}

<u>Find Common Denominator</u>

2: 2,4,6,8,10

4: 4,8,12,16,20

CD=4

<u>Add</u>

1/4+2/4=3/4

3/4=.75

8 0
3 years ago
Read 2 more answers
Help i’m doing my exam
jolli1 [7]
Dude I don’t think using this for an exam is it but ok
5 0
3 years ago
Read 2 more answers
Cooper is measuring ingredients for his special dessert. He needs a total of 70.4 mL of milk and melted butter. The recipe calls
SVETLANKA909090 [29]
21.5m

i think that may be the answer!!
hopefully this helped some?!!!
8 0
3 years ago
Read 2 more answers
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