<span>(5,-1)
The key to this problem is ignoring all the information that you don't need. You really don't care about the coordinates for T, U, or V. Just W is all that matters. So make a graph, label the X and Y axis, and put a point at (1,5). Now simply turn the entire paper clockwise 90 degrees. If you do this, you'll see that what was the X axis is now the Y axis. And what was the Y axis is now the X axis. Label the axis again, and read the location of the point you marked. If you do so, you'll see that you have to go 5 spaces along the X axis, hence the 5. And you'll go 1 space down on the Y axis, hence the -1.
So the coordinates of W(1,5) rotated 90 degrees clockwise around (0,0) changes to (5,-1).</span>
He puts 15 markers in the box. Hope this helps.
Answer:
i guess 3 is the best to remove
Step-by-step explanation:
The bacteria is always doubled because in the sequence we multiply the number by 2
3 x 2 = 6 x 2 = 12 x 2 = 24 x 2 = 48 x 2 = 96
Remark
The formula for this series is
t_n = n^2 - 1
Explanation
If the series ends at 288, then the highest value n can have is 17
So you would write t_n = n^2 - 1 {n| 1 ≤ n ≤17}
If you said this to someone, you would say "t_n = n squared minus 1 where n is such that 1 is greater than or equal to 1 or less than or equal to 17"
Example
What is the 4th term in this series?
t_4 = 4^2 - 1
t_4 = 16 - 1
t_4 = 15
