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Alenkinab [10]
3 years ago
5

Se dispara una bala con una velocidad de v = 300[m/s] contra un cascarón esférico de papel que gira con MCU respecto a un eje ve

rtical. Sabiendo que el radio del cascarón es de 10[cm]. Calcular la rapidez angular mínima que deberá girar el cascarón para que el proyectil haga únicamente un agujero. La dirección del movimiento de la bala pasa por el centro de la esfera.
Physics
1 answer:
Sladkaya [172]3 years ago
7 0

Answer:

 w = 4.712 10⁻³ rad / s

Explanation:

For this exercise, the time it takes for the bullet to travel the distance of 2R must be equal to the time that the hole must travel half a circle.

Let's start by calculating the time it takes for the bullet, which is going at constant speed.

         v = x / t

         t = x / v

         t = 2R / v

         t = 2 0.10 / 300

         t = 6.666 10⁻⁴ s

As they ask that a single hole is formed in this time, it must be rotated half a circle, that is, θ =π rad, for which we use the angular scientific relations, where the shell has constant angular velocity

          w = θ / t

          w = π / 6,666 10⁻⁴

          w = 4.712 10⁻³ rad / s

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98 Points and brainlyest for 5 Science questions please I need it doe before 2:30 ET!!!
Marina CMI [18]
Picture #1:
GPE = (mass) x (gravity) x (height)
GPE = (2 kg) x (9.8 m/s²) x (40 m) = 784 joules

KE = (1/2) (mass) (speed²)
KE = (1/2) (2 kg) (5 m/s)²
KE = (1 kg) (25 m²/s²)  =  25 joules

Picture #2:
KE = (1/2) (mass) (speed²)
KE = (1/2) (2 kg) (10 m/s)²
KE = (1 kg) (100 m²/s²)  =  100 joules

Picture #3:
GPE = (mass) x (gravity) x (height)
GPE = (20 kg) x (9.8 m/s²) x (2 m) = 392 joules

KE = (1/2) (mass) (speed²)
KE = (1/2) (20 kg) (5 m/s)²
KE = (10 kg) (25 m²/s²)  =  250 joules

Picture #4:
GPE = (mass) x (gravity) x (height)
98 joules = (1 kg) x (9.8 m/s²) x (height)
Height = (98 joules) / (1 kg x 9.8 m/s²)
Height = 10 meters

Picture #5:
GPE = (mass) x (gravity) x (height)
39,200 Joules = (mass) x (9.8 m/s²) x (20 m)
Mass = (39,200 joules) / (9.8 m/s² x 20 m)
Mass = 200 kg

5 0
3 years ago
A quartz crystal vibrates with a frequency of 35,621 Hz. What is the period of the crystal's motion?
oksano4ka [1.4K]

Period = 1 / frequency

Period = 1 / (35,621 /s)

Period = 2.8073... x 10⁻⁵ sec

Period = <em>28.07 microseconds</em>

or

Period = <em>0.0281 millisecond</em>

4 0
3 years ago
What do you think will be different about cars in the future? Describe a change that is already being developed or that you thin
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Answer:

Flying cars.

Explanation:

4 0
3 years ago
A man slides on snow without friction starting at 8.96m/s at the top of an inclined plane with height 8.21m. What is his speed a
hammer [34]

Answer:

V2 = 15.53 [m/s]]

Explanation:

In order to solve this problem we must use the principle of energy conservation, where potential energy is transformed into kinetic energy. At the bottom is taken as a reference level of potential energy, where the value of this energy is equal to zero.

Above the inclined plane we have two energies, kinetics and potential. While when the sled is at the reference level all this energy will have been transformed into kinetic energy.

E_{1}=E_{2}\\  m*g*h+(\frac{1}{2} )*m*v_{1} ^{2}=\frac{1}{2}*m*v_{2} ^{2} \\(9.81*8.21)+(0.5*8.96^{2} )=(0.5*v_{2}^{2} )\\(0.5*v_{2}^{2} )=120.68\\v_{2} ^{2}=241.36\\v_{2} =\sqrt{241.36}\\  v_{2} =15.53[m/s]

4 0
2 years ago
When you move your muscles, chemical energy in the cells is converted into mechanical and thermal energy. What is this an exampl
const2013 [10]

Answer:

B.Law of conservation of energy

Explanation:

In physics and chemistry, the law of conservation of energy states that the total energy of an isolated system remains constant; it is said to be conserved over time. This law means that energy can neither be created nor destroyed; rather, it can only be transformed or transferred from one form to another.

plz mark me as brainliest :)

3 0
3 years ago
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