Answer:
the horizontal velocity while it was falling is 22.1 m/s.
Explanation:
Given;
height of fall, h = 16 m
horizontal distance, x = 40 m
The time to travel 16 m is calculated as;
![t = \sqrt{\frac{2h}{g} } \\\\t = \sqrt{\frac{2\times 16}{9.8} } \\\\t = 1.81 \ s](https://tex.z-dn.net/?f=t%20%3D%20%5Csqrt%7B%5Cfrac%7B2h%7D%7Bg%7D%20%7D%20%5C%5C%5C%5Ct%20%3D%20%5Csqrt%7B%5Cfrac%7B2%5Ctimes%2016%7D%7B9.8%7D%20%7D%20%5C%5C%5C%5Ct%20%3D%201.81%20%5C%20s)
The horizontal velocity is calculated as;
![v_x = \frac{X}{t} \\\\v_x = \frac{40}{1.81} \\\\v_x = 22.1 \ m/s](https://tex.z-dn.net/?f=v_x%20%3D%20%5Cfrac%7BX%7D%7Bt%7D%20%5C%5C%5C%5Cv_x%20%3D%20%5Cfrac%7B40%7D%7B1.81%7D%20%5C%5C%5C%5Cv_x%20%3D%2022.1%20%5C%20m%2Fs)
Therefore, the horizontal velocity while it was falling is 22.1 m/s.
Answer:
69000 V
Explanation:
E = Electric field = ![3\times 10^6\ V/m](https://tex.z-dn.net/?f=3%5Ctimes%2010%5E6%5C%20V%2Fm)
d = Distance between plates = 2.3 cm
When we multiply the electric field strength and the distance between the plates of a capacitor we get the maximum voltage.
Maximum voltage is given by
![V_m=Ed\\\Rightarrow V_m=3\times 10^6\times 2.3\times 10^{-2}\\\Rightarrow V_m=69000\ V](https://tex.z-dn.net/?f=V_m%3DEd%5C%5C%5CRightarrow%20V_m%3D3%5Ctimes%2010%5E6%5Ctimes%202.3%5Ctimes%2010%5E%7B-2%7D%5C%5C%5CRightarrow%20V_m%3D69000%5C%20V)
The highest voltage the students can use is 69000 V
Answer:
H=Hydrogen, PO4=Phosphate
Explanation:
Reactions are on the left side of arrow and products are on the right side of arrow.
Answer:
65.1 °C
Explanation:
m = mass of the water = 0.5 kg
= initial temperature of water = 35.00 °C
= final temperature of water
c = specific heat of water = 4186 J/(kg °C)
Q = Amount of heat removed from water = 6.3 x 10⁴ J
Amount of heat removed from water is given as
Q = m c (
-
)
Inserting the values
6.3 x 10⁴ = (0.5) (4186) (
- 35.00)
= 65.1 °C