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Elodia [21]
3 years ago
5

Classify each of the following compounds as an acid, base, or both. Be sure to answer all parts.

Chemistry
1 answer:
Oduvanchick [21]3 years ago
6 0

Explanation:

According to Bronsted-Lowry an acid is defined as the specie which is able to donate hydrogen ions when dissolved in water.

For example, HCl \rightarrow H^{+} + Cl^{-}

On the other hand, bases are the species which are able to donate hydroxide ions when dissolved in water.

For example, NaOH \rightarrow Na^{+} + OH^{-}

In CH_{3}CH_{2}OH compound, when it will lose hydrogen ion then it will result in the formation of a CH_{3}CH_{2}O^{-} (alkoxide ion). As the carbon atoms are donating their positive charge towards the O^{-} ion so, it will become unstable in nature.

As a result, it will neither give a hydrogen ion or a hydroxide ion.

In CH_{3}CH_{2}CH_{2}CH_{3}, there is no difference in the electronegativity of both carbon and hydrogen atoms. Therefore, this compound is not polar in nature hence, it will neither give a hydrogen or hydroxide ion.

In CH_{3}CO_{2}CH_{3} there is presence of no -OH group. Hence, it will neither give a hydroxide or hydrogen ion.

Thus, we can conclude that none of the given compounds will act as an acid or a base.

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Answer:

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Explanation:

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3 years ago
How many grams of K2CO3 are needed to prepare a 400.0 mL of a 4.25M solution?
Basile [38]

Answer:

235 g

Explanation:

From the question;

  • Volume is 400.0 mL
  • Molarity of a solution is 4.25 M

We need to determine the mass of the solute K₂CO₃,

we know that;

Molarity = Number of moles ÷ Volume

Therefore;

First we determine the number of moles of the solute;

Moles = Molarity × volume

Moles of  K₂CO₃ = 4.25 M × 0.4 L

                           = 1.7 moles

Secondly, we determine the mass of  K₂CO₃,

We know that;

Mass = Moles × Molar mass

Molar mass of  K₂CO₃, is 138.205 g/mol

Therefore;

Mass = 1.7 moles × 138.205 g/mol

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Thus, the mass of  K₂CO₃ needed is 235 g

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