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Elodia [21]
3 years ago
5

Classify each of the following compounds as an acid, base, or both. Be sure to answer all parts.

Chemistry
1 answer:
Oduvanchick [21]3 years ago
6 0

Explanation:

According to Bronsted-Lowry an acid is defined as the specie which is able to donate hydrogen ions when dissolved in water.

For example, HCl \rightarrow H^{+} + Cl^{-}

On the other hand, bases are the species which are able to donate hydroxide ions when dissolved in water.

For example, NaOH \rightarrow Na^{+} + OH^{-}

In CH_{3}CH_{2}OH compound, when it will lose hydrogen ion then it will result in the formation of a CH_{3}CH_{2}O^{-} (alkoxide ion). As the carbon atoms are donating their positive charge towards the O^{-} ion so, it will become unstable in nature.

As a result, it will neither give a hydrogen ion or a hydroxide ion.

In CH_{3}CH_{2}CH_{2}CH_{3}, there is no difference in the electronegativity of both carbon and hydrogen atoms. Therefore, this compound is not polar in nature hence, it will neither give a hydrogen or hydroxide ion.

In CH_{3}CO_{2}CH_{3} there is presence of no -OH group. Hence, it will neither give a hydroxide or hydrogen ion.

Thus, we can conclude that none of the given compounds will act as an acid or a base.

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A mixture can be classified as _____ or ______​
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You are asked to perform a reaction by dissolving hypochlorous acid in water. Based on your understanding of acids, you understa
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According to the principle of chemical equilibrium, when additional hypochlorous acid is added, the hypochlorite ion concentration will increase.

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A vessel of 120ml capacity contains a certain amount of gas at 35°C and 1.2 bar pressure. The gas is transferred to another vess
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Given parameters:

Initial volume  = 120ml

Initial temperature  = 35°C

Initial pressure  = 1.2bar

Final volume  = 180ml

Final temperature  = 35°C

Unknown:

Final pressure  = ?

To solve this problem, we apply the combined gas law. The expression is given below;

          \frac{P_{1}V_{1}  }{T_{1} }  = \frac{P_{2}V_{2}  }{T_{2} }

Where P₁ is the initial pressure

           P₂ is the final pressure

          V₁ is the initial volume

          V₂ is the final volume

          T₁ is the initial temperature

           T₂ is the final temperature

We need to convert the parameters to standard units

take the volume to dm³;

      1000ml  = 1dm³

      120ml  = \frac{120}{1000} dm³  = 0.12dm³ = initial volume

Final volume;

      1000ml = 1dm³

      180ml  = \frac{180}{1000} dm³  = 0.18dm³

Now, the temperature;

       K  = 273 + °C

Initial temperature  = 273 + 35  = 308k

Final temperature  = 308k

We then input the parameters into the equation;

         \frac{1.2bar x 0.12 }{308}   = \frac{P_{2} x 0.18 }{308}

       Solving for P₂;

     P₂  = 0.8bar

The new pressure or final pressure in the vessel is 0.8bar

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