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Elodia [21]
3 years ago
5

Classify each of the following compounds as an acid, base, or both. Be sure to answer all parts.

Chemistry
1 answer:
Oduvanchick [21]3 years ago
6 0

Explanation:

According to Bronsted-Lowry an acid is defined as the specie which is able to donate hydrogen ions when dissolved in water.

For example, HCl \rightarrow H^{+} + Cl^{-}

On the other hand, bases are the species which are able to donate hydroxide ions when dissolved in water.

For example, NaOH \rightarrow Na^{+} + OH^{-}

In CH_{3}CH_{2}OH compound, when it will lose hydrogen ion then it will result in the formation of a CH_{3}CH_{2}O^{-} (alkoxide ion). As the carbon atoms are donating their positive charge towards the O^{-} ion so, it will become unstable in nature.

As a result, it will neither give a hydrogen ion or a hydroxide ion.

In CH_{3}CH_{2}CH_{2}CH_{3}, there is no difference in the electronegativity of both carbon and hydrogen atoms. Therefore, this compound is not polar in nature hence, it will neither give a hydrogen or hydroxide ion.

In CH_{3}CO_{2}CH_{3} there is presence of no -OH group. Hence, it will neither give a hydroxide or hydrogen ion.

Thus, we can conclude that none of the given compounds will act as an acid or a base.

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How many moles of hydrogen are present in 5.30 moles of C5H10O2, propyl acetate, the compound that provides the odor and taste o
elena-s [515]

Answer:

Option D. 53 moles.

Explanation:

The following data were obtained from the question:

Number of mole of C5H10O2 = 5.3 moles

Number of mole of Hydrogen in 5.3 moles of C5H10O2 =?

From the chemical formula of propyl acetate, C5H10O2,

1 mole of C5H10O2 contains 10 moles of H.

Therefore, 5.3 moles of C5H10O2 will contain = 5.3 × 10 = 53 moles of H.

Thus, 5.3 moles of C5H10O2 contains 53 moles of H.

5 0
2 years ago
Hydrogen produced from a hydrolysis reaction was collected over water and the following data was compiled.
Shkiper50 [21]

Answer:

  • 0.00358 mol

Explanation:

<u>1) Data:</u>

a) V = 93.90 ml

b) T = 28°C

c) P₁ = 744 mmHg

d) P₂ = 28.25 mmHg

d) n = ?

<u>2) Conversion of units</u>

a) V = 93.90 ml × 1.000 liter / 1,000 ml = 0.09390 liter

b) T = 28°C = 28 + 273.15 K = 301.15 K

c) P₁ = 744 mmHg × 1 atm / 760 mmHg = 0.9789 atm

d) P₂ = 28.5 mmHg × 1 atm / 760 mmHg = 0.0375 atm

<u>3) Chemical principles and formulae</u>

a) The total pressure of a mixture of gases is equal to the sum of the partial pressures of each gas. Hence, the partical pressure of the hydrogen gas collected is equal to the total pressure less the vapor pressure of water.

b) Ideal gas equation: pV = nRT

<u>4) Solution:</u>

a) Partial pressure of hydrogen gas: 0.9789 atm - 0.0375 atm = 0.9414 atm

b) Moles of hygrogen gas:

pV = nRT ⇒ n = pV / (RT) =

n =  (0.9414 atm × 0.09390 liter) / (0.0821 atm-liter /K-mol × 301.15K) =

n = 0.00358 mol (which is rounded to 3 significant figures) ← answer

7 0
3 years ago
Read 2 more answers
0.415 g of an unknown triprotic acid are used to make a 100.00 mL solution. Then 25.00 mL of this solution is transferred to an
Arturiano [62]

Answer:

Explanation:

Initial burette reading = 1.81 mL

final burette reading = 39.7 mL

volume of NaOH used = 39.7 - 1.81 = 37.89 mL .  

37.89 mL of .1029 M NaOH is used to neutralise triprotic acid

No of moles contained by 37.89 mL of .1029 M NaOH

= .03789 x .1029 moles

= 3.89 x 10⁻³ moles

Since acid is triprotic ,  its equivalent weight = molecular weight / 3

No of moles of triprotic acid = 3.89 x 10⁻³ / 3

= 1.30   x 10⁻³ moles .

8 0
3 years ago
Someone plz help me
a_sh-v [17]

Answer:

A experimental investigation

3 0
2 years ago
The equation for the formation of water from hydrogen gas and oxygen gas is 2H2+O2→2H2O.
inn [45]

Answer:

180g

Explanation:

H:1   O:16

2H2+O2 → 2H2O

 2   2(16)       2(1)+(16)

        32              18

Now,

       32g of O → 2(18)g of H2O

       160g of O → 2(18)g divides by 32g times 160g

                            =180g

5 0
3 years ago
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