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3 years ago

What's the value of 3y2 + 2z when y = 4 z= -7

1 answer:

4 0

Y= 4
z= -7

Substitute the given values above in for each variable in the expression below.

= 3y^2 + 2z

= 3(4)^2 + 2(-7)
using order of operations, square 4 before multiplying (PEMDAS: parentheses, exponents, multiplication, division, addition, subtraction)

= 3(16) + (-14)
a positive times negative is negative

= 48 - 14

= 34

ANSWER: 34

Hope this helps! :)

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10. A toy store received a shipment of 17 cases of

ozzi

There are 204 teddy bears in the shipment.

Step-by-step explanation:

Total number of cases received = 17 cases

Numbers of bears per case = 12 bears

Total number of bears in the shipment = Cases received * Bears per case

Total number of bears = $17*12$

Total number of bears = 204

There are 204 teddy bears in the shipment.

Keywords: multiplication

Learn more about multiplication at:

#LearnwithBrainly

8 0

3 years ago

I need help with Which table shows the correct methods used to justify the solution steps?

12345 [234]

Answer:

x = 8

Step-by-step explanation:

3 (x - 5) + 7x = 65

3x - 15 + 7x = 65

10x - 15 = 65

10x = 80

x = 8

5 0

2 years ago

Read 2 more answers

Solve for M -3+m/ 9 = 10

sweet-ann [11.9K]

Step-by-step explanation:

-3+m/9=10

m/9=10+3

m/9=13

m=13×9

m=117

Note:if you need to ask any question please let me know.

5 0

2 years ago

If tan theta =3, find the value of tan theta + tan (theta+pi) + tan (theta +2pi)

sweet-ann [11.9K]

Answer:

$tan\theta + tan(\theta + \pi) + tan(\theta+2\pi) = 9$

Step-by-step explanation:

Given

$tan\theta = 3$

Required

Find

$tan\theta + tan(\theta + \pi) + tan(\theta+2\pi)$

Calculate $tan(\theta + \pi) \ and\ tan(\theta+2\pi)$

Using tan rule

$tan(\theta + \pi) = \frac{tan\theta + tan\pi}{1 - tan\theta tan\pi}$

So:

$tan(\theta + \pi) = \frac{tan\theta + 0}{1 - tan\theta *0}$

$tan(\theta + \pi) = \frac{tan\theta}{1 }$

$tan(\theta + \pi) = \tan\theta$

$tan(\theta+2\pi)$

$tan(\theta + 2\pi) = \frac{tan\theta + tan2\pi}{1 - tan\theta tan2\pi}$

$tan(\theta + 2\pi) = \frac{tan\theta + 0}{1 - tan\theta *0}$

$tan(\theta + 2\pi) = \tan\theta$ '

'So:

$tan\theta + tan(\theta + \pi) + tan(\theta+2\pi)$ $= tan\theta +tan\theta +tan\theta$

$tan\theta + tan(\theta + \pi) + tan(\theta+2\pi) = 3+3+3$

$tan\theta + tan(\theta + \pi) + tan(\theta+2\pi) = 9$

4 0

2 years ago

Write the expression in terms of sin x and cos x only. sin(2x)+cos(3x)

BartSMP [9]

Sin2x=2sinxcosx, cos2x=1-2sin^2x
sin(2x)+cos(3x)=2sinxcosx+cos(x+2x)
cos(x+2x)=cosx(1-2sin^2(x))-sinx2sinxcosx
sin(2x)+cos(3x)=2sinxcosx(1-sinx)+cosx(1-2sin^2(x))

5 0

3 years ago

Read 2 more answers