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stepladder [879]

4 years ago

10

Is this sss, asa, sas or none

2 answers:

Arlecino [84]4 years ago

3 0

Answer: ASA

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Explanation:

ASA stands for "angle side angle"

The first A refers to the bottom left pairs of angles for the triangles. They have one single arc mark to indicate they pair up and are congruent.

The S refers to the bottom sides of the triangle having the same length (the single tickmark shows they are congruent)

The second A is for the pair of angles on the bottom right side of the triangles. These angles have 2 arc marks.

The order of the lettering is important because the S in ASA is between the two angles. As the diagram shows, the sides mentioned are between the angles mentioned. Contrast this with AAS or SAA which has the sides not between the angles.

Lelechka [254]4 years ago

3 0

Definitely sss. hope i helped

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ira [324]

Answer:

a) 0.7291 is the probability that more than half out of 10 vehicles carry just 1 person.

b) 0.996 is the probability that more than half of the vehicles carry just one person.

Step-by-step explanation:

We are given the following information:

A) Binomial distribution

We treat vehicle on road with one passenger as a success.

P(success) = 64% = 0.64

Then the number of vehicles follows a binomial distribution, where

$P(X=x) = \binom{n}{x}.p^x.(1-p)^{n-x}$

where n is the total number of observations, x is the number of success, p is the probability of success.

Now, we are given n = 10

We have to evaluate:

$P(x \geq 6) = P(x =6) +...+ P(x = 10) \\= \binom{10}{6}(0.64)^6(1-0.64)^4 +...+ \binom{10}{10}(0.64)^{10}(1-0.79)^0\\=0.7291$

0.7291 is the probability that more than half out of 10 vehicles carry just 1 person.

B) By normal approximation

Sample size, n = 92

p = 0.64

$\mu = np = 92(0.64) = 58.88$

$\sigma = \sqrt{np(1-p)} = \sqrt{92(0.64)(1-0.64)} = 4.60$

We have to evaluate the probability that more than 47 cars carry just one person.

$P(x \geq 47)$

After continuity correction, we will evaluate

$P( x \geq 46.5) = P( z > \displaystyle\frac{46.5 - 58.88}{4.60}) = P(z > -2.6913)$

$= 1 - P(z \leq -2.6913)$

Calculation the value from standard normal z table, we have,

$P(x > 46.5) = 1 - 0.004 = 0.996 = 99.6\%$

0.996 is the probability that more than half out of 92 vehicles carry just one person.

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3 years ago

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alukav5142 [94]

Answer:

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Step-by-step explanation:

add them and you should get 138.

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