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ehidna [41]
3 years ago
14

Input value for the function machine that gives an output value of 3.

Mathematics
1 answer:
krek1111 [17]3 years ago
3 0

Answer:

x = –1

Step-by-step explanation:

From the question given above, the following data were obtained:

y = √(–2x + 7)

y = 3

x =?

The value of x can be obtained as follow:

y = √(–2x + 7)

3 = √(–2x + 7)

Take the square of both side

3² = –2x + 7

9 = –2x + 7

Collect like terms

9 – 7 = –2x

2 = –2x

Divide both side by –2

x = 2 / –2

x = –1

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tatiyna

Answer:

5

Step-by-step explanation:

8x+50=90

8x=40

x=5

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Rewrite as addition. (Don't add spaces, nor parentheses.) -12- 4*​
OLEGan [10]

You cant. -12-4 = -116

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Dibuja un segmento de 6cm y su mediatriz construye un triángulo con dos de sus vértices en los extremos del segmento y el tercer
yuradex [85]

Answer:

Equilátero si todos sus lados son iguales o isósceles si la base es menor que sus otros dos lados.

Step-by-step explanation:

Revisar fotografía adjunta.

Comienzas dibujando la línea de 6 cm. Luego encuentras su mediatríz, la cual está a 3 centímetros de cualquier extremo de la línea.

Luego dibujas el triángulo como se muestra en el dibujo. Dependiendo de la longitud de los lados, el triángulo podría ser equilátero si todos sus lados son iguales o isósceles si solo los dos lados inclinados son iguales y la base es diferente.

3 0
3 years ago
A recent study focused on the number of times men and women send a WeChat message in a day. The information is summarized next.
Ratling [72]

Answer:

1)Null hypothesis:\mu_{men}=\mu_{women}

Alternative hypothesis:\mu_{men} \neq \mu_{women}

2) Two critical values are z_{\alpha/2}=-2.58 and z_{1-\alpha/2}=2.58

3) z=-2.40  

4) p_v =2*P(z

5) Comparing the p value with the significance level given \alpha=0.01 we see that p_v>\alpha so we can conclude that we FAIL to reject the null hypothesis, and a would NOT be a significant difference in the mean number of times men and women send a Twitter message in a day.

Step-by-step explanation:

Data given and notation

\bar X_{men}=23 represent the mean for the sample men

\bar X_{women}=28 represent the mean for the sample women

\sigma_{men}=5 represent the population standard deviation for the sample men

\sigma_{women}=10 represent the population standard deviation for the sample women

n_{men}=25 sample size for the group men

n_{women}=30 sample size for the group women

t would represent the statistic (variable of interest)

\alpha=0.01 significance level provided

1)Develop the null and alternative hypotheses for this study?

We need to conduct a hypothesis in order to check if the means for the two groups are different, the system of hypothesis would be:

Null hypothesis:\mu_{men}=\mu_{women}

Alternative hypothesis:\mu_{men} \neq \mu_{women}

Since we know the population deviations for each group, for this case is better apply a z test to compare means, and the statistic is given by:

z=\frac{\bar X_{men}-\bar X_{women}}{\sqrt{\frac{\sigma^2_{men}}{n_{men}}+\frac{\sigma^2_{women}}{n_{women}}}} (1)

z-test: Is used to compare group means. Is one of the most common tests and is used to determine whether the means of two groups are equal to each other.

2)Determine the critical value(s).

Based on the significance level\alpha=0.01 and \alpha/2=0.005 we can find the critical values with the normal standard distribution, we are looking for values that accumulates 0.005 of the area on each tail on the normal distribution.

For this case the two values are z_{\alpha/2}=-2.58 and z_{1-\alpha/2}=2.58

3) Calculate the value of the test statistic for this hypothesis testing.

Since we have all the values we can replace in formula (1) like this:

z=\frac{23-28}{\sqrt{\frac{5^2}{25}+\frac{10^2}{30}}}}=-2.40  

4)What is the p-value for this hypothesis test?

Since is a bilateral test the p value would be:

p_v =2*P(z

5)Based on the p-value, what is your conclusion?

Comparing the p value with the significance level given \alpha=0.01 we see that p_v>\alpha so we can conclude that we FAIL to reject the null hypothesis, and a would NOT be a significant difference in the mean number of times men and women send a Twitter message in a day.

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Natali [406]
A 30 days hope this helps
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