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2 years ago

HELPPPPPPPPP i have the most trouble with math what’s the answer??

Mathematics

1 answer:

lakkis [162]2 years ago

6 0

Answer:

Second Option

$\frac{5\sqrt{11} +5\sqrt{3}}{8}$

Step-by-step explanation:

To simplify the expression you must multiply the numerator and the denominator of the fraction by the conjugate of the denominator.

If you have an expression of the form

$a -b$ then its conjugate will be $a + b.$

The result of that multiplication will be

$a ^ 2 -b ^ 2$

Therefore we have the expression

$\frac{5}{\sqrt{11} -\sqrt{3}}$

By multiplying by the conjugate of the denominator we have

$\frac{5}{\sqrt{11} -\sqrt{3}}*\frac{\sqrt{11} +\sqrt{3}}{\sqrt{11} +\sqrt{3}}\\\\\\\frac{5(\sqrt{11} +\sqrt{3})}{(\sqrt{11})^2 -(\sqrt{3})^2}\\\\\\\frac{5\sqrt{11} +5\sqrt{3}}{11 -3}\\\\\\\frac{5\sqrt{11} +5\sqrt{3}}{8}$

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WILL MARK BRAINLIEST!!!!!!!!

SVETLANKA909090 [29]

Data:

15 16 14 15 19 17

n=6 points

sum is 96

mean is 96/6 = 16

Now we look at the absolute deviations, each of which is the absolute value of a score minus the mean, basically the distance of the score to the mean .

Scores 15 16 14 15 19 17

AbsDev 1 0 2 1 3 1

The sum of the absolute deviations is 8 and there are six of them so the

Mean Absolute Deviation = 8/6 = 4/3

Answer: 2. 8/6

7 0

3 years ago

I need the answer for this problem please

Savatey [412]

Answer:

Step-by-step explanation:

Find all probabilities:

A. False

$Pr(\text{red shirt}|\text{large shirt})=\dfrac{\text{number red large shirts}}{\text{number large shirts}}=\dfrac{42}{77}=\dfrac{6}{11}\\ \\Pr(\text{large shirt})=\dfrac{\text{number large shirts}}{\text{number shirts}}=\dfrac{77}{165}=\dfrac{7}{15}$

B. True

$Pr(\text{blue shirt}|\text{large shirt})=\dfrac{\text{number blue large shirts}}{\text{number large shirts}}=\dfrac{35}{77}=\dfrac{5}{11}\\ \\Pr(\text{blue shirt})=\dfrac{\text{number blue shirts}}{\text{number shirts}}=\dfrac{75}{165}=\dfrac{5}{11}$

C. False

$Pr(\text{shirt is medium and blue})=\dfrac{\text{number medium and blue shirts}}{\text{number shirts}}=\dfrac{48}{165}=\dfrac{16}{55}\\ \\Pr(\text{medium shirt})=\dfrac{\text{number medium shirts}}{\text{number shirts}}=\dfrac{88}{165}=\dfrac{8}{15}$

D. False

$Pr(\text{large shirt}|\text{red shirt})=\dfrac{\text{number red large shirts}}{\text{number red shirts}}=\dfrac{42}{90}=\dfrac{7}{15}\\ \\Pr(\text{red shirt})=\dfrac{\text{number red shirts}}{\text{number shirts}}=\dfrac{90}{165}=\dfrac{6}{11}$