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Alex17521 [72]
4 years ago
10

According to Le Chatelier’s principle, a change in pressure affects the chemical equilibrium of the reaction system under what c

ondition? The reactants and the products are in the solid phase. The reactants and the products are in the liquid phase. Some of the reactants or the products are in the gaseous phase. Some of the reactants or the products are solid, and some are liquid.
Chemistry
2 answers:
charle [14.2K]4 years ago
7 0
Some of the reactants or the products are in the gaseous phase.
Eduardwww [97]4 years ago
5 0

C. Some of the reactants or the products are in the gaseous phase.

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Describe how the mass of the product can be calculated when one reactant is in excess
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On the off chance that one of the reactants is in overabundance yet you don't know which one it is, you have to compute the hypothetical item mass for the both reactants, with a similar item, and whichever has the lower yield is the one you use to precisely depict masses/sums for the condition, since you can't have more than the non-abundance reactant can create.
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Why is Nertic zone particularly rich in living things?
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less than 5 centimeters because it is a nonvascular plant

Explanation:

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According to this question, Penny bought a club moss plant for her water garden and needs to know how tall the plant will grow so she know how much space it will need. Since it is a miss plant that lacks vascular tissues i.e. nonvascular, it will likely grow less than 5 centimeters in height.

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3 years ago
Which of these particles are lost in the oxidation process ?
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Upper n subscript 2 (g) plus 3 upper H subscript 2 (g) double-headed arrow 2 upper N upper H subscript 3 (g). At equilibrium, th
artcher [175]

Answer:

The <u>equilibrium constant</u> is:

              k_c=0.0030M^{-2}

Explanation:

The correct equation is:

  •   N₂(g)    +    3H₂(g)    ⇄    2NH₃(g)

Thus, with the equilibrium concentrations you can calculate the equilibrium constant, Kc.

The equation for the equilibrium constant is:

         k_c=\dfrac{[NH_3]^2}{[N_2]\cdot [H_2]^3}

Substituting:

        k_c=\dfrac{(0.105M)^2}{(1.1M)\cdot (1.50M)^3}

         k_c=0.0030M^{-2}

6 0
4 years ago
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