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Arisa [49]
3 years ago
15

• 1) The pressure of a sample of gas in a 2.00-L container is 876 mmHg.

Chemistry
1 answer:
kifflom [539]3 years ago
5 0

Answer:

4380 mmHg

Explanation:

Boyle's Law can be used to explain the relationship between pressure and volume of an ideal gas. The pressure is inversely related to volume, so if volume decrease the pressure will increase. It can be expressed in the equation as:

P1V1=P2V2

In this question, the first condition is 2L volume and 876 mmHg pressure. Then the system changed into the second condition where the volume is 400ml and the pressure is unknown. The pressure will be:

P1V1= P2V2

876 mmHg * 2L = P2 * 400ml /(1000ml/L)

P2= 876 mmHg * 2L / 0.4L

P2= 4380 mmHg

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Answer:

Melting butter

Explanation:

You can reverse the change of butter back to its original state but you can never reverse the rest back to there original state

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3 years ago
Identify each of the following sets of quantum numbers as allowed or not allowed in the hydrogen atom.
Westkost [7]

Answer:

See explanation.

Explanation:

Hello there!

In this case, according to the given information, it turns out possible for us to firstly recall the electron configuration of hydrogen:

1s^1

To realize that the principal quantum number is 1, the angular is 0 as well as the magnetic one; therefore we infer that all the given n's are not allowed, just l=0 is allowed as well as ml=0 yet the rest, are not allowed.

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5 0
3 years ago
What mass of salt is needed to prepare 600 mL of a 4g/L solution?
OLga [1]
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3 years ago
Which is an example of an instinct?
kompoz [17]

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2 years ago
A monoprotic weak acid, HA , dissociates in water according to the reaction HA(aq)↽−−⇀H+(aq)+A−(aq) The equilibrium concentratio
Pachacha [2.7K]

Answer:

pK_{a} of HA is 6.80

Explanation:

pK_{a}=-logK_{a}

Acid dissociation constant (K_{a}) of HA is represented as-

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Where species inside third bracket represents equilibrium concentrations

Now, plug in all the given equilibrium concentration into above equation-

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So, K_{a}=1.6\times 10^{-7}

Hence pK_{a}=-log(1.6\times 10^{-7})=6.80

6 0
3 years ago
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