Can someone pls help :/

Chemistry

1 answer:

jeka57 [31]3 years ago

6 0

Answer:

option C. Addition of protons to the atomic nucleus.

Explanation:

Elements are fundamentally made up of atoms. Atoms in turn has three sub particles.

These particles are; neutrons, electrons and protons.

The sub particles responsible for the mass of an atoms is basically the protons and neutrons. Going through the options;

The correct option is option C. Addition of protons to the atomic nucleus.

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What is the purpose of chemistry?

Brut [27]

Answer:

To know more about chemicals and how to utilise them to solve man's probl

7 0

3 years ago

If a reaction mixture initially contains 0.195 m so2cl2, what is the equilibrium concentration of cl2 at 227 ???c?

Aloiza [94]

Missing in your question the K constant value =2.99X10^-7
The reaction equation:
SOCl2 ⇄ SO2 +Cl2
initial 0.195 0 0
-X +X +X
final (0.195-X) X X

K= [SO2][Cl2]/SOCl2
by substitution
2.99X10^-7 = (X)(X)/(0.195-X)
2.99X10^-7 = X^2 / (0.195-X) by solving this equation
∴X = 0.00024 = 2.4 X10^-4
∴[Cl2] = 2.4X10^-4 m

6 0

3 years ago

Aqueous hydrochloric acid HCl reacts with solid sodium hydroxide NaOH to produce aqueous sodium chloride NaCl and liquid water H

allochka39001 [22]

Answer : The theoretical yield of water formed from the reaction is 0.54 grams.

Solution : Given,

Mass of HCl = 1.1 g

Mass of NaOH = 2.1 g

Molar mass of HCl = 36.5 g/mole

Molar mass of NaOH = 40 g/mole

Molar mass of $H_2O$ = 18 g/mole

First we have to calculate the moles of HCl and NaOH.

$\text{ Moles of }HCl=\frac{\text{ Mass of }HCl}{\text{ Molar mass of }HCl}=\frac{1.1g}{36.5g/mole}=0.030moles$

$\text{ Moles of }NaOH=\frac{\text{ Mass of }NaOH}{\text{ Molar mass of }NaOH}=\frac{2.1g}{40g/mole}=0.525moles$

Now we have to calculate the limiting and excess reagent.

The balanced chemical reaction is,

$HCl+NaOH\rightarrow NaCl+H_2O$

From the balanced reaction we conclude that

As, 1 mole of HCl react with 1 mole of NaOH

So, 0.030 mole of HCl react with 0.030 mole of NaOH

From this we conclude that, $NaOH$ is an excess reagent because the given moles are greater than the required moles and $HCl$ is a limiting reagent and it limits the formation of product.