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3 years ago

A rectangular solid has a length of 3 cm a height of 4 cm and a width of 5 cm what is the solid volume ?

Chemistry

1 answer:

andrew11 [14]3 years ago

3 0

Volume is 60 and the area is 94 have a great day

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How might a theory relate to a model

oksian1 [2.3K]

These are related but can be independent, because it is possible to, the theories are studied in mathematical logic, especially in model theory

8 0

4 years ago

two objects each have a mass of 5.0 g. one had a density of 2.7 g. and the other has a density of 8.4 g. which object has a larg

gulaghasi [49]

Answer:

The body with 2.7 $\frac{g}{(cm^3)}$ has a larger volume

Explanation:

There is a missespelling in the question. The units of density cannot be g, they usually are $\frac{g}{(cm^3)}$

In order to answer this question, we need to use the formula of the density of a body:

$Density = \frac{Mass}{Volume} = \frac{M}{V}$

For body A:

Mass (M) = 5.0 g

Density (D) = 2.7 $\frac{g}{(cm^3)}$

2.7 $\frac{g}{(cm^3)}$ = 5g * 1/V

V1 = 5g / (2.7 $\frac{g}{(cm^3)}$ )

V1 = 1.85 $1.85 cm^3$

For Body B:

Mass (M) = 5.0 g

Density (D) = 8.4 $\frac{g}{(cm^3)}$

8.4 $\frac{g}{(cm^3)}$ = 5g * 1/V

V2 = 5g / (8.4 $\frac{g}{(cm^3)}$ )

V2 = 0.59 $1.85 cm^3$

So V1 is bigger than V2

5 0

3 years ago

10g of helium (MM=4.0g/mol) occupies a volume of 73L at a temperature of 233k. calculate the pressure of this gas

Levart [38]

PV = nRT (where P = pressure; V = volume; n = number of moles; R = gas constant; T = Temperature)
Moles of He = mass of He ÷ molar mass of He = 10 g ÷ 4 g/mol = 2.5 mol

Now, based on the formula above P = (nRT) ÷ V
P = (2.5 mol × (0.082 L · atm/mol · K) × 233 K) ÷ 73 L ≈ 0.65 atm

8 0

3 years ago

Longitude starts at an imaginaryn line running trough greenwich england.Wwhat is the name of immaginary line

sleet_krkn [62]

Answer:

prime meridian

Explanation:

The meridian that runs through Greenwich, England, is internationally accepted as the line of 0 degrees longitude, or prime meridian. The antimeridian is halfway around the world, at 180 degrees. It is the basis for the International Date Line

national geographic

3 0

3 years ago

What is the half-life of a pharmaceutical if the initial dose is 500 mg and only 31 mg remains after 6 hours?

Sergeu [11.5K]

Answer:

$\large \boxed{\text{b. 1.5 h}}$

Explanation:

1. Calculate the rate constant

The integrated rate law for first order decay is

$\ln \left (\dfrac{A_{0}}{A_{t}}\right ) = kt$

where

A₀ and A_t are the amounts at t = 0 and t

k is the rate constant

$\begin{array}{rcl}\ln \left (\dfrac{500}{31}\right) & = & k \times 6\\\\\ln 16.1 & = & 6k\\2.78& =& 6k\\k & = & \dfrac{2.78}{6}\\\\& = & 0.463 \text{ h}^{-1}\\\end{array}$

2. Calculate the half-life

$t_{\frac{1}{2}} = \dfrac{\ln2}{k} = \dfrac{\ln2}{\text{0.463 h}^{-1}} = \textbf{1.5 h}\\\\ \text{The half-life is $\large \boxed{\textbf{1.5 h}}$}$

4 0

3 years ago