Yes, in a way it would, as it would rose out of its container and drift away/apart.

**Answer:**

We are given:

**V(i) = 0.3 L V(f) = 0.36 L**

**P(i) = x pa P(f) = 400 pa**

**T(i) = T(f) = 293 k**

Using the gas formula:

**PV = nRT**

Since n , R and T are constant,

PV = k (where k is a constant)

Hence we can say that:

P(i) * V(i) = P(f) * V(f)

x * 0.3 = 0.36 * 400

x = 14.4/0.3

x = **480 pascals**

**Hence the initial pressure is 480 pascals**

Converting to Kpa, we have to divide by 1000

**Initial pressure (Kpa) = 0.48**

**Answer:**

(a) 11000nm

(b) 9.7 * 10^14 Hz

**Explanation:**

Using velocity = frequency * wavelength