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AveGali [126]
3 years ago
8

Equivalencia de un año luz en SI

Chemistry
1 answer:
Aleksandr [31]3 years ago
4 0
Hi uhh i've never really typed in Spanish but here I go! :)

 Un ano luz es equivalente a 9.467 PM
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Which structure is responsible for bringing in the amino acids? (Points : 1)
Rainbow [258]
Well the answer to number 1 is definitely B
 
number 2 is B

number 3 is D

Number 4 is C

Hope this helps:)



5 0
3 years ago
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Which of the following is not a organic compound, a -corn oil b -b r o m i n e c -m e t h a n e d- protein
Flura [38]
A corn oil. Because oil is treated with a solvent. After that it is refined which gets rid of free fatty acids. Finally, it is sent through steam distillation to get rid of volatile organic compounds.
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3 years ago
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25. 00 ml of a buffer solution contains 0. 500 m hclo and 0. 380 m naclo. if 50. 00 ml of water is added to the buffer, what are
geniusboy [140]

The new concentrations of HClO and NaClO are  0.25M and 19M

Calculation of number of moles of each component,

Molarity of HClO = number of moles/volume in lit =  0. 500 M

Number of moles = molarity  of HClO× volume in lit = 0. 500 M× 0.025 L

Number of moles of HClO = 0.0125 mole

Molarity of NaClO  = number of moles/volume in lit =  0. 38 M

Number of moles = molarity of NaClO × volume in lit = 0. 38 M× 0.025 L

Number of moles of  NaClO  = 0.95 mole

Calculation of new concentration at volume 50 ml ( 0.05L)

Molarity of HClO = number of moles/volume in lit = 0.0125 mole/0.05L

Molarity of HClO = 0.25M

Molarity of NaClO  = number of moles/volume in lit = 0.95mole/0.05L

Molarity of NaClO  = 19 M

learn about  Molarity

brainly.com/question/8732513

#SPJ4

5 0
2 years ago
A sample of hydrated copper (II) sulfate (CuSO4•nH2O) is heated to 150°C and produces 103.74 g anhydrous copper (II) sulfate and
wariber [46]

Answer:

5

Explanation:

Firstly, we convert what we have to percentage compositions.

There are two parts in the molecule, the sulphate part and the water part.

The percentage compositions is as follows:

Sulphate- (103.74)/(103.74 + 58.55) × 100% = apprx 64%

The water part = 100 - 64 = 36%

Now, we divide the percentages by the molar masses.

For the CuSO4 molar mass is 64 + 32 + 4(16) = 160g/mol

For the H2O = 2(1) + 16 = 18g/mol

Now we divide the percentages by these masses

Sulphate = 64/160 = 0.4

Water = 36/18 = 2

The ratio is thus 0.4:2 = 1:5

Hence, there are 5 water molecules.

3 0
3 years ago
Which describes the earth as an open system with respect to energy?
Naddik [55]

Answer:

Explanation:

Any system within the Earth system is considered an open system. Because energy flows freely into and out of systems, all systems respond to inputs and, as a result, have outputs.

6 0
2 years ago
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