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Lostsunrise [7]
3 years ago
13

Prove that the roots of the equation X^2 - 2px + p^2 - q^2 =0 where p and q are constants, are real.

Mathematics
1 answer:
lora16 [44]3 years ago
3 0

Answer:

Step-by-step explanation:

Sorry I am not sure and don’t want to give you the wrong answer sorry again

You might be interested in
An exterior angle of a triangle is 180 degrees.
Lilit [14]
180 degrees of the triage
5 0
2 years ago
3. the smallest number by which 168 must be multipled to get the perfect square number. ICA) 3 1(B)2 (c) 4 (o)5​
kaheart [24]

Answer:

42

Step-by-step explanation:

168 factors into

2•2•2•3•7

two of the 2's make a perfect square

(2•2)•2•3•7

   2²•2•3•7

as none of the product of the remaining factors makes a perfect square

2•3 = 6,  2•7 = 14,  3•7 = 21

we need to multiply the remaining factors together to find another perfect square

   2²•(2•3•7)²

2•3•7 = 42

42(168) = 7056 = 84²

5 0
2 years ago
Please help! acellus
ch4aika [34]

Answer:

The number that belongs <em>in</em> the green box is equal to 909.

General Formulas and Concepts:
<u>Algebra I</u>

Equality Properties

  • Multiplication Property of Equality
  • Division Property of Equality
  • Addition Property of Equality
  • Subtraction Property of Equality

<u>Trigonometry</u>

[<em>Right Triangles Only</em>] Pythagorean Theorem:
\displaystyle a^2 + b^2 = c^2

  • a is a leg
  • b is another leg
  • c is the hypotenuse

Step-by-step explanation:

<u>Step 1: Define</u>

<em>Identify given variables</em>.

<em>a</em> = 30

<em>b</em> = 3

<em>c</em> = <em>x</em>

<em />

<u>Step 2: Find </u><u><em>x</em></u>

Let's solve for the <em>general</em> equation that allows us to find the hypotenuse:

  1. [Pythagorean Theorem] Square root both sides [Equality Property]:
    \displaystyle \begin{aligned}a^2 + b^2 = c^2 \rightarrow c = \sqrt{a^2 + b^2}\end{aligned}

Now that we have the <em>formula</em> to solve for the hypotenuse, let's figure out what <em>x</em> is equal to:

  1. [Equation] <em>Substitute</em> in variables:
    \displaystyle \begin{aligned}c & = \sqrt{a^2 + b^2} \\x & = \sqrt{30^2 + 3^2}\end{aligned}
  2. <em>Evaluate</em>:
    \displaystyle \begin{aligned}c & = \sqrt{a^2 + b^2} \\x & = \sqrt{30^2 + 3^2} \\& = \boxed{ \sqrt{909} } \\\end{aligned}

∴ the hypotenuse length <em>x</em> is equal to √909 and the number <em>under</em> the square root, our answer, is equal to 909.

___

Learn more about Trigonometry: brainly.com/question/27707750

___

Topic: Trigonometry

3 0
2 years ago
Jamar's teacher told him that one of the reasons he gave on the proof below was incorrect. Which reason did he make the mistake
Kamila [148]

Answer:

Reason given in step 2. is incorrect. It should read; "Distributive Property."

Step-by-step explanation:

The reason given to go from :

2 (3x +4) = 56  to 6x + 8 = 56

is NOT "Multiplication Property of Equality" because one is not multiplying both sides of the equality by a number. The property that is being used is the Distributive Property on the left side of the equation in order to remove the grouping symbols (parenthesis) performing the implied multiplication of the external factor times each term of the binomial in parenthesis.

8 0
3 years ago
F(x) = 4x-5; f(-2)<br> please help
Firdavs [7]

Answer:

f(x)=-13

Step-by-step explanation:

Substitute x with -2

4 times -2 is -8

-8-5 is -13

Thus f(x)=-13

Hope this helps!

5 0
3 years ago
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