Prove that the roots of the equation X^2 - 2px + p^2 - q^2 =0 where p and q are constants, are real.
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Answer:
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Sorry I am not sure and don’t want to give you the wrong answer sorry again
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Step-by-step explanation:
Answer:
Step-by-step explanation:
Substituting y = 4x+1 into 2y = -x-1 gives the equation
2(4x+1) = -x-1
Solve the equation:
8x+2 = -x-1
9x = -3
x = -⅓
