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Diano4ka-milaya [45]
3 years ago
10

Which of these correlation numbers shows the strongest relationship? +.46 +.32 -0.41 -0.68

Physics
1 answer:
Kobotan [32]3 years ago
6 0
Answer: -0.068

Explanation:
A familiar correlation number of R² denotes the degree of correlation between measured data and the curve of best fir
R² = 1 denotes a perfect fit, so that
R = +1, or R = -1 denotes a perfect fit.
R² = 0 denotes no correlation.

To compare the given correlation numbers, we should consider their absolute values. In decreasing order, they are
-0068 => 0.68
0.46    => 0.46
-0.041  => 0.41
0.32    => 0.32
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BaLLatris [955]

Answer:

C. Ocean currents change the temperature of air masses. Warm ocean currents transport heat from the equator to the poles.

Explanation:

Ocean currents act much like a conveyor belt, transporting warm water and precipitation from the equator toward the poles and cold water from the poles back to the tropics. Thus, ocean currents regulate global climate, helping to counteract the uneven distribution of solar radiation reaching Earth's surface

3 0
3 years ago
A charge of uniform linear density 2.00 nC/m is distributed along a long, thin, nonconducting rod. The rod is coaxial with a lon
NemiM [27]

Answer:

(a) E=233.56 N/C

(b) The surface charge density of inner surface  σ= -5.69×10⁻⁹C/m²

(c)The surface charge density of outer surface  σ= 3.25×10⁻⁹C/m²

Explanation:

For Part (a)

The magnitude of the electric field at distance of 15.4 cm from the axis of the shell is given by:

E=λ/2πε₀r

Substitute the given values

E=\frac{2.00*10^{-9} }{2\pi 8.854*10^{-12}*0.154 }\\ E=233.56N/C

Since the nonconducting rod positively charged,it induces a negative charge -q on the inner surface of conducting shell and a positive charge +q on the outer surface of conducting shell,so the net charge of conducting shell is zero

Part (b)

The surface charge density of inner surface is given by:

σ=-q/A

=\frac{-q}{2\pi r_{inner} l}\\ =\frac{\frac{-q}{l} }{2\pi r_{inner}}\\

= -λ/2πr

=\frac{-2.0*10^{-9} }{2\pi (0.056)}\\ =-5.69*10^{-9}C/m^{2}

Part(c)

Similarly the surface charge density on the outer surface of the cylindrical shell given by:

σ=λ/2πr

=\frac{2.0*10^{-9} }{2\pi 0.098}\\ =3.25*10^{-9}C/m^{2}  

 

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3 years ago
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Sliding friction is harder to overcome, and steals
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That's why we switched from sleds to wheels
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8 0
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If you pour different liquids into a graduated cylinder, which layer would be at the bottom?
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the one that is more dense!

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4 years ago
The sun emits __________ radiation, but it is radiated back off of planetary bodies as __________ radiation.
andriy [413]
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