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Helen [10]
4 years ago
5

The three forces acting on a hot-air balloon that is moving vertically are its weight, the force due to air resistance and the u

pthrust force.
The hot-air balloon descends vertically at constant speed. The force of air resistance on the balloon is F.
Which weight of material must be released from the balloon so that it ascends vertically at the same constant speed?
Physics
1 answer:
Aleksandr [31]4 years ago
3 0
Let
upthrust = T
weight = W = mg
Air resistance = F

When balloon is descending, air resistance acts upwards (positive)
By Newton's first law, the net force on the balloon is zero, or
T+F-W=0......................(1)

Let w=weight of material dumped so that balloon now travels upwards at constant speed.
Air resistance acts against motion, namely downwards.
The Newton's equation now reads
T-F-(W-w)=0................(2)

Subtract (2) from (1)
T+F-W - (T-F-(W-w)) = 0
Solve for w
w=2F, or
the WEIGHT of material to be released equals twice the resistance of air.
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Force the glove exerts on the ball

Explanation:

The reaction to this force is the force the glove exerts on the ball.

According to Newton's third ;aw of motion "Action and reaction forces are equal and opposite in direction".

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This reactive force is directed in the opposite direction and it is the reason why the motion of the incoming ball is halted.

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at a drag race, the light turns green and 0.00125 hours later, a dragster is travelling 300 miles per hour. Calculate the accele
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<span>240,000 miles / hour² Average acceleration can be calculated by dividing the change in speed by the elapsed time. Since the dragster's speed was 0 when the light turned green, the change in speed is simply 300 mph. Now, divide that by the time: 300 mph / 0.00125 hours = 240,000 miles / hour² By the way, 0.00125 hours is just 4.5 seconds!</span>
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The grand canal was built to make easier the transportation of grains to the power center of north china.

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What are the potential obstacles preventing you from completing your exercises as scheduled? How can you overcome those obstacle
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Problem 20.75 A thin rectangular coil 2 cm by 9 cm has 44 turns of copper wire. It is made to rotate with angular frequency 110
NeTakaya

Answer:

(a) 16.5528 V

(b) 827.64 W

Explanation:

(a)

The formula for maximum emf produced in a coil is given as

E₀ = BANω.................. Equation 1

Where E₀ = maximum emf produced in the coil, B = magnetic Field, A = Area of the rectangular coil, N = number of turns, ω = angular velocity.

Given: B = 1.9 T, N = 44 turns, ω = 110 rad/s, A = 2×9 = 18 cm² = 18/10000 = 0.0018 m²

Substitute into equation 1

E₀ = 1.9(44)(110)(0.0018)

E₀ = 16.5528 V

(b)

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P₀ = E₀²/R...................... Equation 2

Where R = Resistance.

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Substitute into equation 2

P₀ = 50(16.5528)

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