Answer:
20.05 seconds
Explanation:
Given that:
v² = u² + 2as
v = final velocity
u = initial velocity
a = acceleration
s = distance
a = negative acceleration = - 0.43
s = distance = 86.5
v = 0
0 - 2(0.43)(86.5) = u²
74.39 = v²
U = sqrt(74.39)
U = 8.6249
From ;
t = Time in seconds
t = (v - u) / a
t = (0 - 8.6249) / - 0.43
t = 20.057
The kelvin temperature/scale i think
I think B......................
Answer:
1 kg
Explanation:
The container has negligible mass and no heat is loss to the surrounding.
Mass of ice = 0.4kg, initial temperature of ice = -29oC, final temperature of the mixture = 26oC, mass of water (m2) = ?kg, initial temperature of water = 80oC, c ( specific heat capacity of water ) = 4200J/kg.K, Lf = heat of fusion of water = 3.36 × 10^5 J/kg
Using the formula:
Quantity of heat gain by ice = Quantity of heat loss by water
Quantity of heat gain by ice = mass of ice × heat of fusion of ice + mass of water × specific heat capacity of water = (0.4 × 3.36 × 10^ 5) + (0.4 × 4200 × (26- (-29) = 13.44 × 10^4 + 9.24 × 10^ 4 = 22.68 × 10^4 J
Quantity of heat loss by water = m2cΔT
Quantity of heat loss by water = m2 ×4200× (80 - 26) = m(226800)
since heat gain = heat loss
22.68 × 10^4 = 226800 m2
divide both side by 226800
226800 / 226800 = m2
m2 = 1 kg
Answer:
Explanation:
Use that:
Then use the 2nd Newton's Law of Motion:
At x = 0.3 and y = 0.6, we can find the acceleration as:
(in SI unit)
Then the magnitude of the acceleration on that point is:
(SI Unit)
