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shusha [124]
4 years ago
7

If you pour different liquids into a graduated cylinder, which layer would be at the bottom?

Physics
1 answer:
klasskru [66]4 years ago
5 0

the one that is more dense!

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A 200 kg man is stuck, motionless, in the middle of a frictionless ice pond. Because it's cold, he's wearing a coat. He wants to
Cerrena [4.2K]

The speed of the man when he throws the coat is 1 m/s.

<h3>Conversion of linear momentum</h3>

The speed of the man can be determined by applying the principle of conservation of linear momentum as follows;

m₁v₁ = m₂v₂

v₁ = (m₂v₂)/m₁

v₁ = (50 x 4)/200

v₁ = 1 m/s

Thus, the speed of the man when he throws the coat is 1 m/s.

Learn more about conservation of momentum here: brainly.com/question/7538238

7 0
2 years ago
During a compaction test in the lab a cylindrical mold with a diameter of 4in and a height of 4.58in was filled. The compacted s
Ray Of Light [21]

Answer:

part a : <em>The dry unit weight is 0.0616  </em>lb/in^3<em />

part b : <em>The void ratio is 0.77</em>

part c :  <em>Degree of Saturation is 0.43</em>

part d : <em>Additional water (in lb) needed to achieve 100% saturation in the soil sample is 0.72 lb</em>

Explanation:

Part a

Dry Unit Weight

The dry unit weight is given as

\gamma_{d}=\frac{\gamma}{1+\frac{w}{100}}

Here

  • \gamma_d is the dry unit weight which is to be calculated
  • γ is the bulk unit weight given as

                                              \gamma =weight/Volume \\\gamma= 4 lb / \pi r^2 h\\\gamma= 4 lb / \pi (4/2)^2 \times 4.58\\\gamma= 4 lb / 57.55\\\gamma= 0.069 lb/in^3

  • w is the moisture content in percentage, given as 12%

Substituting values

                                              \gamma_{d}=\frac{\gamma}{1+\frac{w}{100}}\\\gamma_{d}=\frac{0.069}{1+\frac{12}{100}} \\\gamma_{d}=\frac{0.069}{1.12}\\\gamma_{d}=0.0616 lb/in^3

<em>The dry unit weight is 0.0616  </em>lb/in^3<em />

Part b

Void Ratio

The void ratio is given as

                                                e=\frac{G_s \gamma_w}{\gamma_d} -1

Here

  • e is the void ratio which is to be calculated
  • \gamma_d is the dry unit weight which is calculated in part a
  • \gamma_w is the water unit weight which is 62.4 lb/ft^3 or 0.04 lb/in^3
  • G is the specific gravity which is given as 2.72

Substituting values

                                              e=\frac{G_s \gamma_w}{\gamma_d} -1\\e=\frac{2.72 \times 0.04}{0.0616} -1\\e=1.766 -1\\e=0.766

<em>The void ratio is 0.77</em>

Part c

Degree of Saturation

Degree of Saturation is given as

S=\frac{G w}{e}

Here

  • e is the void ratio which is calculated in part b
  • G is the specific gravity which is given as 2.72
  • w is the moisture content in percentage, given as 12% or 0.12 in fraction

Substituting values

                                      S=\frac{G w}{e}\\S=\frac{2.72 \times .12}{0.766}\\S=0.4261

<em>Degree of Saturation is 0.43</em>

Part d

Additional Water needed

For this firstly the zero air unit weight with 100% Saturation is calculated and the value is further manipulated accordingly. Zero air unit weight is given as

\gamma_{zav}=\frac{\gamma_w}{w+\frac{1}{G}}

Here

  • \gamma_{zav} is  the zero air unit weight which is to be calculated
  • \gamma_w is the water unit weight which is 62.4 lb/ft^3 or 0.04 lb/in^3
  • G is the specific gravity which is given as 2.72
  • w is the moisture content in percentage, given as 12% or 0.12 in fraction

                                      \gamma_{zav}=\frac{\gamma_w}{w+\frac{1}{G}}\\\gamma_{zav}=\frac{0.04}{0.12+\frac{1}{2.72}}\\\gamma_{zav}=\frac{0.04}{0.4876}\\\gamma_{zav}=0.08202 lb/in^3\\

Now as the volume is known, the the overall weight is given as

weight=\gamma_{zav} \times V\\weight=0.08202 \times 57.55\\weight=4.72 lb

As weight of initial bulk is already given as 4 lb so additional water required is 0.72 lb.

4 0
3 years ago
Given the recent evidence suggesting that species change due to a certain genetic variations, what would be true?
boyakko [2]

Answer:

c) mutation and natural selection both cause changes in a population

Explanation:

Hope it help

Mark me as brainliest

6 0
3 years ago
Please help... <br> !!!!!!!
Scilla [17]

Answer:

1) C. The precise location of weather-related phenomena

2) C. It shows that the galaxies are moving farther away.

Explanation:

1) The global positioning system can be used in many ways, like in navigation, mapping and surveying the land. It is also used to observe the small changes taking place in the movement of objects on earth. They are usually used to study earthquakes.

2) When light from the galaxies is shifted towards the longer wavelengths, it is called red shift. When light shifts towards the shorter wavelengths, it is called blue shift. Big bang theory states how the primordial universe started expanding from a hot and dense singularity, in the process of evolution of the universe.

The  universe is expanding always. Galaxies that are a part of the universe keep expanding and move farther away from each other. The galaxies that are very far off appear to  move much faster than the nearby galaxies.

6 0
3 years ago
If the incoming photon had a frequency of 8.0 E14 Hz, would you have a photo-electron ejected?
cupoosta [38]

Yes.


In fact, from the graph we see that the threshold frequency (the minimum energy of the incoming energy needed to extract a photoelectron from the material) is 5.0 \cdot 10^{14} Hz (we see it because this is the frequency at which the maximum kinetic energy of the emitted electron is zero).


The incoming photon in this problem has a frequency of 8.0 E14 Hz, so above the threshold frequency, therefore it is enough to extract photoelectrons from the material.

4 0
4 years ago
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