Answer:
The pressure of the air molecules inside the pen cap increases and the volume occupied by the air decreases such that the combined volume occupied by the pen cap and the air volume reduces while the combined mass of the pen cap and the air molecules remain the same
Given that density = The mass/Volume, we have that the density varies inversely as the volume, and as the volume reduces, the density increases
Upon squeezing, therefore, as the new combined density of the pen cap and the air molecules rises to more than the density of the water in the bottle, then, the pen cap air molecule is relatively more denser than the water, which will result in the pen cap sinking to the bottom of the bottle
Explanation:
The correct option is: (C) <span>when one does not have enough resources to satisfy all of one’s wants
Explanation:
Scarcity in Economics is defined as the "unlimited wants and limited resources." If a someone's wants cannot be satisfied because of the limited resources, then it signifies the condition of scarcity. Hence in the options given the only option that satisfies this definition is option C. </span>
Answer:
∴The air cannot be made to flow in with the given pump at the given conditions.
Explanation:
Given:
- gauge pressure of bicycle tyre,
- length of cylinder of the pump,
- area of the the cylinder of the pump,
- we have the density of air at STP,
The piston must be pushed more than the pressure inside the tyre:
∴The air cannot be made to flow in with the given pump at the given conditions.
Answer:
V is approximately = 23m/s
Explanation:
Kinetic energy = ½ mv²
Where m= mass = 0.450kg
V= velocity =?
K. E = 119J
Therefore
K. E = ½ mv²
Input values given
119= ½ × 0.450 × v²
Multiply both sides by 2
119 ×2 = 2 × 1/2 × 0.450 × v²
238= 0.450v²
Divide both sides by 0.450
238/0.450 = 0.450v²/0.450
v² = 528.89
Square root both sides
Sq rt v² = sq rt 528.89
V = 22.998m/s
V is approximately = 23m/s
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<h2>
Answer: zero (0)</h2>
Explanation:
The orbit of a body around another in space, is described by six orbital elements that determine its orientation, position, size and shape.
In the specific case of the shape of the orbit, this is determined by its <u>eccentricity</u>, which varies between 0 and 1 in the case of closed orbits (circle and ellipse). When the eccentricity is 0, the shape of the orbit is circular, when this value begins to vary until approaching 1 (without reaching 1), the shape of the orbit becomes more elliptical.
In this sense, a circular orbit will have an eccentriciy of zero.