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shusha [124]
3 years ago
7

If you pour different liquids into a graduated cylinder, which layer would be at the bottom?

Physics
1 answer:
klasskru [66]3 years ago
5 0

the one that is more dense!

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What is the difference in force of a car and a tractor
vodka [1.7K]

Answer:

See a tractor is more slow but has a greater force and a car is fast but has a slower force

Explanation:

so your answer is Tractors have more force then cars

6 0
3 years ago
A car moves with an initial velocity of 19 m/s due north. (Part A) Find the velocity of the car after 5.6 s if its acceleration
galben [10]

Answer

Assuming

east is the positive x direction

north is the positive y direction

initial velocity , u = 19 j m/s

a) acceleration , a = 1.6 j m/s^2

Using first equation of motion

v = u + a × t

v = 19 + 5.6× 1.6

v = 28 j m/s

the velocity of the car after 5.6 s is 28 m/s north

b)

acceleration , a = -1.5 j m/s^2

Using first equation of motion

v = u + a × t

v = 19 - 5.6 ×1.5

v = 10.6 j m/s

the velocity of the car after 5.6 s is 10.6 m/s north

5 0
3 years ago
4- Protein foods?? pls answer these i really need these​
vampirchik [111]

The #1 answer would be meats and eggs. But, as a veggan, I present you with meatless protien-rich food!

1 - <u>Pea protein</u> (used in Beyond Meat, which tastes just like meat btw!)

2 - <u>Soy protein</u> such as tofu

3 - <u>Nuts</u>

4 - <u>Beans</u>! oml so many beans have MORE protien than meat!! ikr!?!?

may I have Brainliest pls =)

8 0
2 years ago
Instructions:Select the correct answer from the drop-down menu. The Longmenshan Fault is in China. This fault was created when t
lina2011 [118]
I say Reverse Fault, Hope this helps :)
3 0
3 years ago
A 75-m-long train begins uniform acceleration from rest. the the train has a speed of 23 m/s when it passes a railway worker tan
Lapatulllka [165]

Answer:

acceleration a = 1.04 m/s2

Explanation:

Assume the train has a speed of 23m/s when the last car passes the railway workers. Once this happens the last car would have traveled a total distance of the 180m distance between the railway worker standing 180 m from where the front of the train started plus the 75m distance from the first car to the last car:

s = 75 + 180 = 255 m

We can use the following equation of motion to find out the distance traveled by the car:

v^2 - v_0^2 = 2aswhere v = 23 m/s is the velocity of the car when it passes the worker, v_0 = 0m/s is the initial velocity of the car when it starts, a m/s2 is the acceleration, which we are looking for.

23^2 - 0^2 = 2*a*255

510a = 529

a = 529 / 510 = 1.04 m/s^2

8 0
3 years ago
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