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hjlf
3 years ago
7

there are 20 students in the group , 15 from them are athletes. it is taken for competition 10 students. find the probability th

at 10 students are 5 athlet​
Mathematics
2 answers:
Alona [7]3 years ago
6 0
500 jdjdjdjjsdjjjssosoe
NeX [460]3 years ago
5 0

Answer:

500

Step-by-step explanation:

50 divided by 10 is 9

You might be interested in
What is the length of LM if L(3,4) and M(1,-2)? Round to the nearest tenth.
kari74 [83]

Answer:

We conclude that the length of LM if L(3,4) and M(1,-2) will be:

d = 6.3

Hence, option D is correct.

Step-by-step explanation:

Given

  • L(3,4)
  • M(1,-2)

Determining the length of LM

  • (x₁, y₁) = (3, 4)
  • (x₂, y₂) = (1, -2)

The length of the distance between (x₁, y₁)  and (x₂, y₂)  can be determined using the formula

d=\sqrt{\left(x_2-x_1\right)^2+\left(y_2-y_1\right)^2}

substituting (x₁, y₁) = (3, 4) and (x₂, y₂) = (1, -2)

   =\sqrt{\left(1-3\right)^2+\left(-2-4\right)^2}

   =\sqrt{2^2+6^2}

   =\sqrt{4+36}

   =\sqrt{40}

   =\sqrt{4\times 10}

   =\sqrt{2^2\times \:10}

   =2\sqrt{10}

   =6.3

Therefore, we conclude that the length of LM if L(3,4) and M(1,-2) will be:

d = 6.3

Hence, option D is correct.

5 0
2 years ago
Can y’all help me answer these questions
cupoosta [38]

2. f(x)=\dfrac18\left(\dfrac14\right)^{x-2}

Domain: (-\infty,\infty), because any value of x is allowed and gives a number f(x).

Range: (0,\infty), because a^x>0 for any positive real a\neq0.

y-intercept: This is a point of the form (0, f(0)). So plug in x=0; we get f(0)=\frac18\left(\frac14\right)^{-2}=\frac{4^2}8=2. So the intercept is (0, 2), or just 2. (Interestingly, you didn't get marked wrong for that...)

Asymptote: This can be deduced from the range; the asymptote is the line y=0.

Increasing interval: Going from left to right, there is no interval on which f(x) is increasing, since 1/4 is between 0 and 1.

Decreasing interval: Same as the domain; f(x) is decreasing over the entire real line.

End behavior: The range tells you f(x)>0, and you know f(x) is decreasing over its entire domain. This means that f(x)\to+\infty as x\to-\infty, and f(x)\to0 and x\to+\infty.

3. f(x)=\left(\dfrac32\right)^{-x}-7

Domain: Same as (2), (-\infty, \infty).

Range: We can rewrite f(x)=\left(\frac23\right)^x-7. \left(\frac23\right)^x>0 for all x, so \left(\frac23\right)^x-7>-7 for all x. Then the range is (-7,\infty).

y-intercept: We have f(0)=\left(\frac32\right)^0-7=1-7=-6, so the intercept is (0, -6) (or just -6).

Asymptote: y=-7

Increasing interval: Not increasing anywhere

Decreasing interval: (-\infty,\infty)

End behavior: Similar to (2), but this time f(x)\to+\infty as x\to-\infty and f(x)\to-7 as x\to+\infty.

5 0
3 years ago
What is the value of A?
Artemon [7]

Answer:

101

Step-by-step explanation:

The theorem to use this is the intercepted arc theorem, which tells us that if we take 2 points on the circumference of a circle and create an angle in the opposite side of the circumference, that angle is HALF that of the ARC intercepted.

If we look at 100 degree angle, we see the ARC intercepted is 99 degree and a degrees. According to theorem, we can say:

99 + a = 2(100)

99 + a = 200

a = 200 - 99

a = 101

6 0
3 years ago
What are the square roots of; (note: i think there are supposed to be 2 each) 36 12 1.96 0.64 400 25/36
Goryan [66]

Answer:

36 : 6 and -6

12 = 2\sqrt{3} ,  -2\sqrt{3}

1.96 =1.4 and -1.4

0.64 : 0.8 and -0.8

400 : 20 and -20

25/36 = 5/6 and -5/6

Step-by-step explanation:

we know that

(-x)^2 = x^2

ALSO

(x)^2 = x^2

thus, square of both negative and positive number is same positive number.

_________________________________________________

36 = 6*6

36 = -6*-6

hence

square roots of 36 is both -6 and 6

12 = 4*3 = 2^2*\sqrt{3} *\sqrt{3}

\sqrt{12} = 2\sqrt{3}

also

12 = -2\sqrt{3} *-2\sqrt{3}

\sqrt{12} = -2\sqrt{3}

___________________________________

1.96 = 196/100 = (14/10)^2

1.96 = 196/100 = (-14/10)^2

hence

\sqrt{1.96}  = 14/10  \ or -14/10

_______________________________

0.64 = 64/100 = (8/10)^2 = 0.8^2

0.64 = 64/100 = (-8/10)^2 = (-0.8)^2

Thus, square root of  0.64 = 0.8 and -0.8

_________________________________

400 = 20^2

400 = (-20)^2

\sqrt{400}  = 20\\\sqrt{400}  = -20\\

__________________________________

25/36 = (5/6)^2

25/36 = (-5/6)^2

\sqrt{ 25/36} = 5/6 \\\sqrt{ 25/36} = (-5/6

7 0
2 years ago
Please Show the work
Svetradugi [14.3K]

the answer is a) because its the numerator is bigger than the denominator

8 0
3 years ago
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