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mylen [45]
3 years ago
7

Which is the correct order of materials in terms of reflectivity, from least to greatest?brown soil, beige sand, white paper, bl

ack asphalt
Chemistry
2 answers:
Digiron [165]3 years ago
8 0

Answer:

Black Asphalt < Brown Soil < Beige Sand < White Paper (from smallest to greatest)

Explanation:

The reflectivity here refers to the reflection of light, which is the amount of light that is reflected back when incident on the surface of any particles.

Black asphalts are black colored, viscous liquid form of petroleum that is often used for the construction of roads. It is black in color and is a good absorber of heat.

Brown soil is the brownish colored earth soils that are basically comprised of mineral matters, water, humus, and also some living organisms are found to be present here. These mineral matter are the rock fragments that were formed from weathering and erosion of rocks. They have a low reflectivity of light.

Beige sand are the reddish-brown colored feldspar particles that can absorb as well as release heat up to some extent.

White papers are good reflectors of light because of its light white color that enables the incident light to reflect back into the atmosphere.

Thus, the reflectivity of the materials are given below in the increasing order as-

Black Asphalt < Brown Soil < Beige Sand < White Paper.

m_a_m_a [10]3 years ago
7 0
I think it's black asphalt, brown soil, beige sand, white paper. I'm sorry if I'm wrong.
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A student dissolves of glucose in of a solvent with a density of . The student notices that the volume of the solvent does not c
nikitadnepr [17]

Answer:

0.052 M

0.059 m

Explanation:

There is some missing info. I think this is the complete question.

<em>A student dissolves 4.6 g of glucose in 500 mL of a solvent with a density of 0.87 g/mL. The student notices that the volume of the solvent does not change when the glucose dissolves in it. Calculate the molarity and molality of the student's solution. Round both of your answers to 2 significant digits.</em>

Step 1: Calculate the moles of glucose (solute)

The molar mass of glucose is 180.16 g/mol.

4.6 g × 1 mol/180.16 g = 0.026 mol

Step 2: Calculate the molarity of the solution

0.026 moles of glucose are dissolved in 500 mL (0.500 L) of solution. We will use the definition of molarity.

M = moles of solute / liters of solution

M = 0.026 mol / 0.500 L = 0.052 M

Step 3: Calculate the mass corresponding to 500 mL of the solvent

The solvent has a density of 0.87 g/mL.

500 mL × 0.87 g/mL = 435 g = 0.44 kg

Step 4: Calculate the molality of the solution

We will use the definition of molality.

m = moles of solute / kilograms of solvent

m = 0.026 mol / 0.44 kg = 0.059 m

4 0
3 years ago
What does “like dissolves like” mean?
Tems11 [23]

Answer:

c  solvents dissolve chemicals with the same polarity ( ex. both are polar)

Explanation:

Like dissolves like is one of the central rule that guides the solubility of one substance in another.

  • It fully suggests substance having the same nature as in polarity-wise will dissolve one another.
  • For example, water is a polar liquid, it will dissolve table salt because it i also polar.
  • Water cannot dissolve oil because oil is non-polar.
4 0
3 years ago
Iron has a density of 7.86 g/cm3 and a mass of 3.76 kg. calculate the volume
DaniilM [7]
Density = Mass / Volume

Input the values in their respective places and then use algebra to solve for volume.

Hope that helps.
7 0
3 years ago
A scientist is investigating the structure of aluminum nitrate, which has the chemical formula Al(NO3)3. Based on the chemical f
bekas [8.4K]
The chemical formula of aluminium nitrate is - Al(NO₃)₃
cation is Al³⁺
anion is NO₃⁻
One Al atom binds to three nitrate groups 
the options given are 
2. <span>It has three aluminum (Al) atoms 
this is incorrect as there's only one Al atom 
3. </span><span>It has one NO3 group.
this is incorrect as there are three nitrate groups
4. </span><span>It has nine nitrogen (N) atoms
there are only 3 N atoms therefore this too is incorrect 
</span>therefore the correct answer is - 
It has three NO₃<span> groups


</span>
6 0
3 years ago
How much energy must be removed from a 94.4 g sample of benzene (molar mass= 78.11 g/mol) at 322.0 K to solidify the sample and
Kay [80]

Answer : The energy removed must be, 29.4 kJ

Explanation :

The process involved in this problem are :

(1):C_6H_6(l)(322K)\rightarrow C_6H_6(l)(279K)\\\\(2):C_6H_6(l)(279K)\rightarrow C_6H_6(s)(279K)\\\\(3):C_6H_6(s)(279K)\rightarrow C_6H_6(s)(205K)

The expression used will be:  

Q=[m\times c_{p,l}\times (T_{final}-T_{initial})]+[m\times \Delta H_{fusion}]+[m\times c_{p,s}\times (T_{final}-T_{initial})]

where,

Q = heat released for the reaction = ?

m = mass of benzene = 94.4 g

c_{p,s} = specific heat of solid benzene = 1.51J/g^oC=1.51J/g.K

c_{p,l} = specific heat of liquid benzene = 1.73J/g^oC=1.73J/g.K

\Delta H_{fusion} = enthalpy change for fusion = -9.8kJ/mol=-\frac{9.8\times 1000J/mol}{78g/mol}=-125.6J/g

Now put all the given values in the above expression, we get:

Q=[94.4g\times 1.73J/g.K\times (279-322)K]+[94.4g\times -125.6J/g]+[94.4g\times 1.51J/g.K\times (205-279)K]

Q=-29427.312J=-29.4kJ

Negative sign indicates that the heat is removed from the system.

Therefore, the energy removed must be, 29.4 kJ

3 0
3 years ago
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