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mylen [45]
3 years ago
7

Which is the correct order of materials in terms of reflectivity, from least to greatest?brown soil, beige sand, white paper, bl

ack asphalt
Chemistry
2 answers:
Digiron [165]3 years ago
8 0

Answer:

Black Asphalt < Brown Soil < Beige Sand < White Paper (from smallest to greatest)

Explanation:

The reflectivity here refers to the reflection of light, which is the amount of light that is reflected back when incident on the surface of any particles.

Black asphalts are black colored, viscous liquid form of petroleum that is often used for the construction of roads. It is black in color and is a good absorber of heat.

Brown soil is the brownish colored earth soils that are basically comprised of mineral matters, water, humus, and also some living organisms are found to be present here. These mineral matter are the rock fragments that were formed from weathering and erosion of rocks. They have a low reflectivity of light.

Beige sand are the reddish-brown colored feldspar particles that can absorb as well as release heat up to some extent.

White papers are good reflectors of light because of its light white color that enables the incident light to reflect back into the atmosphere.

Thus, the reflectivity of the materials are given below in the increasing order as-

Black Asphalt < Brown Soil < Beige Sand < White Paper.

m_a_m_a [10]3 years ago
7 0
I think it's black asphalt, brown soil, beige sand, white paper. I'm sorry if I'm wrong.
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What expression approximates the volume of O2 consumed, measure at STP, when 55 g of Al reacts completely with excess O2?2 Al(s)
nikdorinn [45]

Answer : The volume of O_2 consumed are, 0.75\times 2\times 22.4 L.

Explanation :

The balanced chemical reaction will be:

4Al(s)+3O_2(g)\rightarrow 2Al_2O_3(s)

First we have to calculate the moles of Al.

\text{Moles of }Al=\frac{\text{Mass of }Al}{\text{Molar mass of }Al}

Molar mass of Al = 27 g/mole

\text{Moles of }Al=\frac{55g}{27g/mol}=2mole

Now we have to calculate the moles of O_2.

From the reaction we conclude that,

As, 4 mole of Al react with 3 moles of O_2

So, 2 mole of Al react with \frac{3}{4}\times 2=0.75\times 2 moles of O_2

Now we have to calculate the volume of O_2 consumed.

As we know that, 1 mole of substance occupies 22.4 liter volume of gas.

As, 1 mole of O_2 occupies 22.4 liter volume of O_2 gas

So, 0.75\times 2 mole of O_2 occupies 0.75\times 2\times 22.4 liter volume of O_2 gas

Therefore, the volume of O_2 consumed are, 0.75\times 2\times 22.4 L.

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3 years ago
The atomic number and the mass number of 18 and 40. Write the information conveyed by this statement.​
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What’s the formula for Lithium acetate
notsponge [240]

Answer:

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Explanation:

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