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mylen [45]
3 years ago
7

Which is the correct order of materials in terms of reflectivity, from least to greatest?brown soil, beige sand, white paper, bl

ack asphalt
Chemistry
2 answers:
Digiron [165]3 years ago
8 0

Answer:

Black Asphalt < Brown Soil < Beige Sand < White Paper (from smallest to greatest)

Explanation:

The reflectivity here refers to the reflection of light, which is the amount of light that is reflected back when incident on the surface of any particles.

Black asphalts are black colored, viscous liquid form of petroleum that is often used for the construction of roads. It is black in color and is a good absorber of heat.

Brown soil is the brownish colored earth soils that are basically comprised of mineral matters, water, humus, and also some living organisms are found to be present here. These mineral matter are the rock fragments that were formed from weathering and erosion of rocks. They have a low reflectivity of light.

Beige sand are the reddish-brown colored feldspar particles that can absorb as well as release heat up to some extent.

White papers are good reflectors of light because of its light white color that enables the incident light to reflect back into the atmosphere.

Thus, the reflectivity of the materials are given below in the increasing order as-

Black Asphalt < Brown Soil < Beige Sand < White Paper.

m_a_m_a [10]3 years ago
7 0
I think it's black asphalt, brown soil, beige sand, white paper. I'm sorry if I'm wrong.
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The temperature of a sample of liquid water changes from 50°C to 30°C. Which statement best explains the change
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Answer:

The molecules move slower than the temp of 50°c and their average kinetic energy decreases.

Explanation:

kinetic energy cannot increase as temperature is reduced. molecules will still move with reduced motion.

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The change in entropy is related to the change in the number of moles of gas molecules. Determine the change in moles of gas for
tester [92]

The given question is incomplete. The complete question is:

The change in entropy is related to the change in the number of moles of gas molecules. Determine the change in moles of gas for each of the reactions and decide if the entropy increases decreases or has little to no change:

A. K(s)+O_2(g)\rightarrow KO_2(s)

B. CO(g)+3H_2(g)\rightarrow CH_4(g)+H_2O(g)

C. CH_4(g)+2O_2(g)\rightarrow CO_2(g)+2H_2O(g)

D. N_2O_2(g)\rightarrow 2NO(g)+O_2(g)

Answer: A. K(s)+O_2(g)\rightarrow KO_2(s) : decreases

B. CO(g)+3H_2(g)\rightarrow CH_4(g)+H_2(g) : decreases

C. CH_4(g)+2O_2(g)\rightarrow CO_2(g)+2H_2O(g): no change

D. N_2O_2(g)\rightarrow 2NO(g)+O_2(g) : increases

Explanation:

Entropy is defined as the randomness of the system.

Entropy is said to increase when the randomness of the system increase, is said to decrease when the randomness of the system decrease and is said to have no change when the randomness remains same.

In reaction K(s)+O_2(g)\rightarrow KO_2(s), as gaseous reactant is changed to solid product, entropy decreases.

In reaction CO(g)+3H_2(g)\rightarrow CH_4(g)+H_2O(g), as 4 moles of gaseous reactants is changed to 2 moles of gaseous product, entropy decreases.

In reaction CH_4(g)+2O_2(g)\rightarrow CO_2(g)+2H_2O(g), as 3 moles of gaseous reactants is changed to 3 moles of gaseous product, entropy has no change.

In reaction  N_2O_2(g)\rightarrow 2NO(g)+O_2(g) , as 1 mole of gaseous reactant is changed to 3 moles of gaseous product, entropy increases.

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CH₃-CH₂-OH → CH₂=CH₂ + H₂O

Learn more about:

sulphuric acid

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