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saw5 [17]
3 years ago
6

Why would it be more difficult to inject the nucleus of uranium with a proton?

Chemistry
1 answer:
nasty-shy [4]3 years ago
4 0

Answer:

Because there are already 92 protons in the

uranium nucleus, combining their repulsive power to reject the one new one. However, if the energy of the incoming proton is sufficiently great, then at extremely close distance, the uranium nucleus will attract the proton and draw it into the nucleus. This is called the strong force.

16 S 33

Explanation:

I hope it helped

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How long must $542 be invested at a rate of 7% to earn $303.52 in interest
yulyashka [42]

The number of years that must be invested at  a rate of 7 % to earn$ 303.52 in interest is

    8 years

 <em><u>calculation</u></em>

  • <em><u> </u></em><em>by use of  the formula       A = P (1+  rt) </em>
  • <em>  where :  A  is the final amount  =  542 + 303.52  =$ 845.52</em>

<em>                    P  is the principal   money to be invested =  $ 542</em>

<em>                        r= rate= 7/100=0.07</em>

<em>                       t=  time required</em>

<em>=$ 845.52=$ 542( 1+  0.07 t)</em>

  • <em>open the  bracket</em>
  • <em>= $845.53= $542 + $37.94  t</em>

  • <em>like terms  together</em>

    =$  845.53 -$542  = $37.94 t

   =$303.52 =$37.94 t

  • divide both  side by  $37.94

  =  $303.52/ $   37.94  =  $37.94t/$37.94

  t=  8 years

7 0
3 years ago
In the following experiments, identify the
Sonja [21]
The tire pressure
Independent variable
Increases as the temperature increases
Dependent variable
hope I helped!
6 0
3 years ago
Read 2 more answers
Which of the term best describe the developing country? Select the three
Romashka-Z-Leto [24]

A developing country (or a low and middle income country (LMIC), less developed country, less economically developed country (LEDC), or underdeveloped country) is a country with a less developed industrial base and a low Human Development Index (HDI) relative to other countries.

8 0
4 years ago
Read 2 more answers
The wall of an industrial furnace is constructed from 0.15-m-thick, fireclay brick having a thermal conductivity of LZ W/m.K. Me
aliya0001 [1]

Answer:

The rate of heat loss through the wall is 1700 watts.

Explanation:

The complete statement of the problem is:

<em>The wall of an industrial furnace is constructed from 0.15-m-thick, fireclay brick having a thermal conductivity of 1.7 W/m·K. Measurements made during steady state operation reveal temperatures of 1400 and 1150 K at the inner and outer sur- faces, respectively. What is the rate of heat loss through a wall that is 0.5 m by 1.2 m on a side?</em>

Given that wall of the industrial furnace is under steady conditions of heat transfer and whose configuration is a flat element, we use the equation of conductive heat transfer rate (\dot Q), measured in watts:

\dot Q = \frac{k\cdot w\cdot h}{l}\cdot (T_{i}-T_{o})

Where:

k - Thermal conductivity, measured in watts per meter-Kelvin.

w - Width of the wall, measured in meters.

h - Height of the wall, measured in meters.

l - Thickness of the wall, measured in meters.

T_{i} - Inner surface temperature, measured in Kelvin.

T_{o} - Outer surface temperature, measured in Kelvin.

If we know that k = 1.7 \,\frac{W}{m\cdot K}, w = 1.2\,m, h = 0.5\,m, l = 0.15\,m, T_{i} = 1400\,K and T_{o} = 1150\,K, the steady state heat transfer is:

\dot Q = \left[\frac{\left(1.7\,\frac{W}{m\cdot K} \right)\cdot (1.2\,m)\cdot (0.5\,m)}{0.15\,m} \right]\cdot (1400\,K-1150\,K)

\dot Q = 1700\,W

The rate of heat loss through the wall is 1700 watts.

3 0
3 years ago
What is the percent yield of a reaction in which 47.5 g tungsten (VI) oxide (WO3) reacts with excess hydrogen gas to produce met
Katarina [22]

Answer:

The percent yield of a reaction is 85.04%

Explanation:

:WO_3+3H_2\rightarrow W+3H_2O

Mass of WO_3 = 47.5g

Molar mass of WO_3 = 232 g/mole

Molar mass of H_2O= 18 g/mole

Volume of water obtained from the reaction , V= 9.40mL

Mass of water = m = Experimental yield of water

Density of water = d = 1.00 g/mL

M=d\times V = 1.00 g/mL\times 9.40 mL=9.40 g

Moles of tungsten(VI) oxide =\frac{47.5 g}{232 g/mol}=0.2047 mol

According to recation 1 mole of tungsten(VI) oxide gives 3 moles of water, then 0.2047 moles of tungsten(VI) oxide will give:

\frac{3}{1}\times 0.2047 mol=0.6141 mol

Mass of 0.6141 moles of water:

0.6141 mol × 18 g/mol = 11.054 g

To calculate the percentage yield of reaction , we use the equation:

% yield = {\frac{Experimental yield}{theoretical yield} \times 100

\frac{9.40}{11.054} \times 100\\\\= 85.04

The percent yield of a reaction is 85.04%

7 0
3 years ago
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