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saw5 [17]
3 years ago
6

Why would it be more difficult to inject the nucleus of uranium with a proton?

Chemistry
1 answer:
nasty-shy [4]3 years ago
4 0

Answer:

Because there are already 92 protons in the

uranium nucleus, combining their repulsive power to reject the one new one. However, if the energy of the incoming proton is sufficiently great, then at extremely close distance, the uranium nucleus will attract the proton and draw it into the nucleus. This is called the strong force.

16 S 33

Explanation:

I hope it helped

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A nickle is about 2 millimeters thick, or 2/1000 of a meter.how many nanometers is this?
Softa [21]
You know that you can just google it right? It has this converter.
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3 years ago
Determine the composition of each phase in a cu-40% ni alloy at 1300c,
Morgarella [4.7K]
To be able to answer this, you need to have a phase diagram of Cu-Ni alloy. Create a vertical line along 40% in the x-axis. Then, create a horizontal line along the temperature at 1,300°C. The intersection lies outside of the α-L boundary. <em>Therefore, the system consist solely of the L-phase: 100% L.</em>

4 0
3 years ago
Which of the following is/are part of the nitrogen cycle?
Pachacha [2.7K]
Denitrification is part of the nitrogen cycle 
7 0
3 years ago
Lysol Power Toilet Bowl Cleaner contains 9.5% hydrochloric acid. Explain why this would be necessary to clean toilet bowls that
Romashka [77]

Answer:

The acid will absolutely remove the hard water deposits that are trapping the stains. The longer it soaks, the less you have to scrub. It works for hard water stains, limescale, and rust!

Explanation:

hope this helped you out.

8 0
3 years ago
Data was collected by students in an acid base titration lab. They used 1.63 M Ca(OH)2(AQ)
jenyasd209 [6]

Answer:

3.8 M

Explanation:

Volume of acid used VA= 57.0 - 37.5 = 19.5 ml

Volume of base used VB= 67.8 - 45.0 = 22.8 ml

Equation of the reaction

2HNO3(aq) + Ca(OH)2(aq) --------> Ca(NO3)2(aq) + 2H2O(l)

Number of moles of acid NA= 2

Number of moles of base NB= 1

Concentration of acid CA= ???

Concentration of base CB= 1.63 M

CAVA/CBVB = NA/NB

CAVANB = CBVBNA

CA= CBVBNA/VANB

CA= 1.63 × 22.8 × 2/ 19.5 × 1

CA= 3.8 M

HENCE THE MOLARITY OF THE ACID IS 3.8 M.

6 0
2 years ago
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