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3 years ago

6

Why would it be more difficult to inject the nucleus of uranium with a proton?

1 answer:

nasty-shy [4]3 years ago

4 0

Answer:

Because there are already 92 protons in the

uranium nucleus, combining their repulsive power to reject the one new one. However, if the energy of the incoming proton is sufficiently great, then at extremely close distance, the uranium nucleus will attract the proton and draw it into the nucleus. This is called the strong force.

16 S 33

Explanation:

I hope it helped

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How many moles are in 3.57 x 10 32<br> particles Ca?

valentina_108 [34]

Answer:

$\boxed {\boxed {\sf 592,826,303.6 \ moles \ of \ Ca }}$

Explanation:

To convert from moles to particles, we must Avogadro's Number.

$6.022*10^{23}$

This number tells us the number of particles (atoms, ions, molecules, etc.) in 1 mole of a substance. In this case, it is the particles of calcium in 1 mole of calcium.

$6.022*10^{23} \ particles \ Ca / mole \ Ca$

We can use Avogadro's Number as a ratio or fraction.

$\frac{6.022 *10^{23} \ particles \ Ca}{1 \ mol \ Ca}$

Multiply this by the given number of particles (3.57*10³²).

$3.57*10^{32} \ particles \ Ca*\frac{6.022 *10^{23} \ particles \ Ca}{1 \ mol \ Ca}$

Flip the fraction so the particles of calcium will cancel out.

$3.57*10^{32} \ particles \ Ca*\frac{1 \ mol \ Ca}{6.022 *10^{23} \ particles \ Ca}$

$3.57*10^{32} *\frac{1 \ mol \ Ca}{6.022 *10^{23} }$

$\frac{3.57*10^{32} \ mol \ Ca}{6.022 *10^{23} }$

$592826303.6 \ mol \ Ca$

There are <u>592,826,303.6 moles</u> of calcium in 3.57*10³² particles of calcium.

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2 years ago

What is the difference between a group and a period

Rasek [7]

In a periodic table periods are horizontal and groups are vertical. Horizontal is left to right and vertical is up and down.
Hope this helps!

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Answer:

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Which has the strongest intermolecular forces

Elina [12.6K]

Answer:

I think it is B

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lana66690 [7]

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Explanation:

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