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g100num [7]
4 years ago
11

A student is working in a lab to determine how time affects impulse. The student keeps the force the same in each trial but chan

ges the impact time. Some data is shown.

Physics
2 answers:
notsponge [240]4 years ago
8 0

Answer:

Trail 3

Explanation:

As we know by Newton's II law that rate of change in momentum is always net force applied on the object.

Here we know that

F = \frac{\Delta P}{\Delta t}

now we also know that change in momentum is known as impulse

so here impulse and force relation is given as

impulse = F\Delta t

so here in order to find the greatest impulse we need to find the product of force and time to be the maximum as per above formula

so we have

trail 1

impulse = 500 (0.25) = 125 Ns

trial 2

impulse = 500(0.15) = 75 Ns

trial 3

impulse = 500(0.45) = 225 Ns

trial 4

impulse = 500(0.33) = 165 Ns

so out of the four trials maximum impulse is for trial 3

pishuonlain [190]4 years ago
4 0

yea some data is shown what is the question dude

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You push very hard on a heavy desk, trying to move it. You do work on the desk:
frozen [14]

Answer:

(C) Only if it starts moving

Explanation:

We know that work done is given by

W=F.d=Fdcos\Theta

So there are two case in which work done is zero

First case is that when force and displacement are perpendicular to each other

And other case is that when there is no displacement

So for work to be done there must have displacement, if there is no displacement then there is no work done

So option (c) will be the correct option

3 0
3 years ago
Jacques is trying to put a screw into a hard piece of wood, but it is too difficult for him to turn. Which of the following woul
solniwko [45]

Answer:

A. It is the only one that makes sense

Explanation:

3 0
4 years ago
What kinds of birds visits you a feeder at different times a year
likoan [24]

Purple finches, chickadees,cardinals,blue jays,woodpeckers,red polls,juncos,goldfinches,and red crossbills.

6 0
4 years ago
Which of the following statements are true for electric field lines? Check all that apply. Check all that apply. Electric field
Scilla [17]

Answer:

Electric field lines point away from positive charges and toward negative charges. <u>True</u>

Electric field lines are continuous; they do not have a beginning or an ending.<u> False</u>

Electric field lines can never intersect. <u>True</u>

Electric field lines are close together in regions of space where the magnitude the electric field is weak and are father apart where it is strong. <u>False</u>

At every point in space, the electric field vector at that point is tangent to the electric field line through that point.<u> True</u>

Explanation:

Electric field lines point away from positive charges and toward negative charges. Always the field lines go to negative charges and leave from positive charges.

Electric field lines are continuous; they do not have a beginning or an ending.<u> False  </u>

Because the field lines starts at positive charges and ends in negative charges.

Electric field lines can never intersect. <u>True</u>

It can not intercept the field lines because in that point the the field would have two directions. Besides, in that point the real value of the field should be found adding both field lines.

Electric field lines are close together in regions of space where the magnitude the electric field is weak and are father apart where it is strong. <u>False</u>

This fact is opposite to that so the regions of space where the magnitude the electric field is weak the lines are father apart and where the field is strong  the lines are close together.

At every point in space, the electric field vector at that point is tangent to the electric field line through that point.<u> True</u>

This statement correspond to the definition of the field line.

5 0
3 years ago
What is the energy of the photon that could cause (a) an electronic transition from then= 4 state to the n 5 state of hydrogen a
Fiesta28 [93]

Answer:

a) E_photon =0.306 eV

b) E_photon =0.166 eV

Explanation:

The energy of the photon (E) for n^th orbit of the hydrogen atom is given as:

E_photon = E_o(\frac{1}{n_{1}^{2}}-\frac{1}{n_{2}^{2}})

where,

E_o = 13.6 eV

n = orbit

a) Now for the transition from n = 4 to n = 5

E_photon =13.6(\frac{1}{4^{2}}-\frac{1}{5^{2}})

E_photon =0.306 eV

b) Now for the transition from n = 5 to n = 6

E_photon =13.6(\frac{1}{5^{2}}-\frac{1}{6^{2}})

E_photon =0.166 eV

7 0
3 years ago
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