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3 years ago

Give a real life example in which two objects are moving at a constant speed but have different velocities.

Physics

2 answers:

Bad White [126]3 years ago

6 0

Answer:

The planets and moons that orbit in the solar system.

Explanation:

For example the earth moves at 67,000 mph (107,000 km/h), and is constant from the gravitational pull of the sun. The moon orbits at about 2,288 mph (3,683 km/h). these are both traveling at different velocities but at a constant speed.

Andreyy893 years ago

4 0

Two cars are driving in opposite directions on the same street. One car is driving North at 30 mph, while the other one is on the other side of the street, driving South at 30 mph.

Both cars have the same speed. But their velocities are different, because DIRECTION is part of velocity.

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The density of gasoline is 730 kg/m3 at 0°C. Its average coefficient of volume expansion is 9.60 10-4(°C)−1. Assume 1.00 gal of

kipiarov [429]

Answer: 0.4911 kg

Explanation:

We have the following data:

$\rho_{0\°C}= 730 kg/m^{3}$ is the density of gasoline at $0\°C$

$\beta=9.60(10)^{-4} \°C^{-1}$ is the average coefficient of volume expansion

We need to find the extra kilograms of gasoline.

So, firstly we need to transform the volume of gasoline from gallons to $m^{3}$ :

$V=8.50 gal \frac{0.00380 m^{3}}{1 gal}=0.0323 m^{3}$ (1)

Knowing density is given by: $\rho=\frac{m}{V}$ , we can find the mass $m_{1}$ of 8.50 gallons:

$m_{1}=\rho_{0\°C}V$

$m_{1}=(730 kg/m^{3})(0.0323 m^{3})=23.579 kg$ (2)

Now, we have to calculate the factor $f$ by which the volume of gasoline is increased with the temperature, which is given by:

$f=(1+\beta(T_{f}-T_{o}))$ (3)

Where $T_{o}=0\°C$ is the initial temperature and $T_{f}=21.7\°C$ is the final temperature.

$f=(1+9.60(10)^{-4} \°C^{-1}(21.7\°C-0\°C))$ (4)

$f=1.020832$ (5)

With this, we can calculate the density of gasoline at $21.7\°C$ :

$\rho_{21.7\°C}=730 kg/m^{3} f=(730 kg/m^{3})(1.020832)$

$\rho_{21.7\°C}=745.207 kg/m^{3}$ (6)

Now we can calculate the mass of gasoline at this temperature:

$m_{2}=\rho_{21.7\°C}V$ (7)

$m_{2}=(745.207 kg/m^{3})(0.0323 m^{3})$ (8)

$m_{2}=24.070 kg$ (9)

And finally calculate the mass difference $\Delta m$ :

$\Delta m=m_{2}-m_{1}=24.070 kg-23.579 kg$ (10)

$\Delta m=0.4911 kg$ (11) This is the extra mass of gasoline

6 0

3 years ago

at room temperature, iron is a solid and mercury is a liquid. based on this information we can infer thata. iron has a higher bo

olchik [2.2K]

A. iron has a higher boiling point thanmercury.

8 0

3 years ago

Read 2 more answers

A submarine travels 25 km/h north for 3.2 hours. What is its displacement?

Vika [28.1K]

displ = velocity x time

25 x 3.2 = 75+5 km north.

7 0

3 years ago

Read 2 more answers

how does spatial pattern of heights illustrate the relationship between temperature density and the rate of vertical pressure ch

Anika [276]

The rate of change of vertical pressure is directly proportional to density and also directly proportional to temperature.

Generally, the relationship between temperature, density and rate of vertical pressure is given as;

$\rho = \frac{PM}{RT}$

$\frac{dP}{dz} = -\rho g\\\\$

where;

ρ is density
T is temperature
dP is rate of change of vertical pressure

Thus, from the formula above, we can conclude the following relationship between temperature, density and the rate of vertical pressure change in spatial pattern of heights.

The rate of change of vertical pressure is directly proportional to density and also directly proportional to temperature.

Learn more here:brainly.com/question/25395377

5 0

3 years ago

Which of the following is a simple machine? A. wedge B. meat grinder C. car D. bicycle

kati45 [8]

I think the answer is D. Bicycle

4 0

3 years ago