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Sedaia [141]
3 years ago
10

A shopping cart given an initial velocity of 2.0 m/s undergoes a constant acceleration of 3.0 m/s2. What is the magnitude of the

cart’s displacement after the first 4.0 s of its motion?
Physics
1 answer:
Tema [17]3 years ago
6 0

Answer:

32 m

Explanation:

initial velocity (u) = 2 m/s

accceleration (a) = 3 m/s^{2}

time (t) = 4 s

What is the magnitude of the cart’s displacement (s) after the first 4.0 s of its motion?

from the equation of motion, displacement (s) = ut + 0.5at^{2}

where

  • u is the initial velocity
  • t is the time
  • a is the acceleration

inserting all required values into  (s) = ut + 0.5at^{2}          

(s) = 2x4 + 0.5x3x4^{2}

s = 8 + 24

s = 32 m

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This is the same question that I just answered.

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