Question

A shopping cart given an initial velocity of 2.0 m/s undergoes a constant acceleration of 3.0 m/s2. What is the magnitude of the cart’s displacement after the first 4.0 s of its motion?

Answer 1

Answer:

32 m

Explanation:

initial velocity (u) = 2 m/s

accceleration (a) = 3 m/s^{2}

time (t) = 4 s

What is the magnitude of the cart’s displacement (s) after the first 4.0 s of its motion?

from the equation of motion, displacement (s) = $ut + 0.5at^{2}$

where

• u is the initial velocity
• t is the time
• a is the acceleration

inserting all required values into  (s) = $ut + 0.5at^{2}$          

(s) = $2x4 + 0.5x3x4^{2}$

s = 8 + 24

s = 32 m