Yes, I believe it will put points on your license. I think in some cases you will get your license revoked
Answer:
the coefficient of Kinetic friction between the tires and road is 0.38
Option A) .38 is the correct answer
Explanation:
Given that;
final velocity v = 0
initial velocity u = 15m/s
time taken t = 4 s
acceleration a = ?
from the equation of motion
v = u + at
we substitute
0 = 15 + a × 4
acceleration a = -15/4 = - 3.75 m/s²
the negative sign tells us that its a deacceleration so the sign can be ignored.
Deacceleration due to friction a = μ × g
we substitute
3.75 = μ × 9.8
μ = 3.75 / 9.8 = 0.3826 ≈ 0.38
Therefore the coefficient of Kinetic friction between the tires and road is 0.38
Option A) .38 is the correct answer
No, they won't, mass coincides with density and objects have different densities a one pound lead ball would be smaller than a one pound copper one.
Firstly an atom has electrons , protons and neutrons. The protons are positively charged and the electrons are negatively charged and the neurons are neutral. So in a neutral atom the amount of protons equals to the amount of electrons. Thus the protons and neutrons can be called particles
Answer:
Explanation:
Force constant of spring K = 21 N /m
we shall find the common velocity of putty-block system from law of conservation of momentum .
Initial momentum of putty
= 5.3 x 10⁻² x 8.97
= 47.54 x 10⁻² kg m/s
If common velocity after collision be V
47.54 x 10⁻² = ( 5.3x 10⁻² + .454) x V
V = .937 m/s
If x be compression on hitting the putty
1/2 k x² = 1/2 m V²
21 x² = ( 5.3x 10⁻² + .454) x .937²
x² = .0212
x = .1456 m
14.56 cm
