Answer:
Phylum Annelida commonly referred as segmented worms possess long , cylindrical and segmented body .
Phylum Aschelminthes commonly referred as round worms possess long , cylindrical , unsegmented body and show sexual dimorphism .
Phylum Echinodermata which includes star fish have tube feet as locomotory organ .
Phylum Porifera commonly referred as pore bearing animals and are diploplastic which includes euspongia etc.
Answer:
a) 14 Ω
b) 2.0 A
c) 28 V
Explanation:
a) The total resistance of resistors in series is the sum:
R = R₁ + R₂
R = 8.0 Ω + 6.0 Ω
R = 14 Ω
b) The current in the 6.0 Ω resistor can be found with Ohm's law:
V = IR
12 V = I (6.0 Ω)
I = 2.0 A
c) Since the resistors are in series, they have the same current. So the total voltage is:
V = IR
V = (2.0 A) (14 Ω)
V = 28 V
<span>Place a test charge in the middle. It is 2cm away from each charge.
The electric field E= F/Q where F is the force at the point and Q is the charge causing the force in this point.
The test charge will have zero net force on it. The left 30uC charge will push it to the right and the right 30uC charge will push it to the left. The left and right force will equal each other and cancel each other out.
THIS IS A TRICK QUESTION.
THe electric field exactly midway between them = 0/Q = 0.
But if the point moves even slightly you need the following formula
F= (1/4Piε)(Q1Q2/D^2)
Assume your test charge is positive and make sure you remember two positive charges repel, two unlike charges attract. Draw the forces on the test charge out as vectors and find the magnetude of the force, then divide by the total charge to to find the electric field strength:)</span>
