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Mariana [72]
3 years ago
12

Ammonium perchlorate (NH4ClO4) is the solid rocket fuel used by the U.S. Space Shuttle. It reacts with itself to produce nitroge

n gas (N2), chlorine gas (Cl2), oxygen gas (O2), water (H2O), and a great deal of energy. What mass of nitrogen gas is produced by the reaction of 9 gr of ammonium perchlorate? Round your answer to significant digits.

Chemistry
1 answer:
Temka [501]3 years ago
6 0

Answer:

1.08 grams of nitrogen

Explanation:

Thermally ammonium perchlorate dissociate as shown in figure.

Thus as per equation two moles of ammonium perchlorate will give four moles of water, two moles of oxygen, one mole of chlorine and one mole of nitrogen,

The molar mass of ammonium perchlorate = 117.5g/mol

Two moles of ammonium perchlorate = 2X  117.5 = 234 g

The molar mass of nitrogen = 28g

thus 234 grams of ammonium perchlorate will give 28 grams of nitrogen

Hence 9 grams of ammonium perchlorate will give 1.08 grams of nitrogen

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Raising the temperature of 10.0 g of water from 10.0 °C to 20.0 °C requires 100.0 cal of energy, while raising the temperature o
djyliett [7]

Answer:

Explanation:

The change in enthalpy of a substance when heated is given by

ΔH = m x Csp x ΔT

so the enthalpy change is dependent on the specific heat , i.e its capactity to absorb heat, and is not influenced by factors such as being closer to the melting point, volume , potential energy or being a solid or liquid.

6 0
3 years ago
When the volume of a gas is changed from 524 cm^3 to ____ cm^3, the temperature will change from 491 K to 297 K .
SpyIntel [72]
V1/T1=V2/T2
524 cm^3/491 K =V2/297K

V2=(524 cm^3*297K)/491 K= 317K
5 0
3 years ago
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Mole ratio of co2 carbonate to water
tino4ka555 [31]
Pls make ur question alittle clearer by may be saying the chemical compound or writing the required reaction

4 0
3 years ago
Ammonia gas combines with excess oxygen gas to produce nitric oxide and water. How many grams of ammonia gas would have to react
Sedbober [7]

Answer:

11.6g of NH₃(g) have to react

Explanation:

For the reaction:

4 NH₃(g) + 5 O₂(g) → 4 NO(g) + 6 H₂O(g) ΔH = -905kJ

<em>4 moles of ammonia produce 905kJ</em>

Thus, if you want to produce 154kJ of energy you need:

154kJ × (4 mol NH₃ / 905kJ) = <em>0.681moles of NH₃. </em>In mass -Molar mass ammonia is 17.031g/mol-

0.681mol NH₃ × (17.031g / mol) = <em>11.6g of NH₃(g) have to react</em>

3 0
3 years ago
If a system performs 147 kJ of work while receiving 47 kJ of heat, what is change in its internal energy?
Verdich [7]

Answer:

-100 kJ

Explanation:

We can solve this problem by applying the first law of thermodynamics, which states that:

\Delta U = Q-W

where:

\Delta U is the change in internal energy of a system

Q is the heat absorbed/released by the system (it is positive if absorbed by the system, negative if released by the system)

W is the work done by the system (it is positive if done by the system, negative if done on the system)

For the system in this problem we have:

W = +147 kJ is the work done by the system

Q = +47 kJ is the heat absorbed by the system

So , its change in internal energy is:

\Delta U = +47 - (+147) =-100 kJ

6 0
3 years ago
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