<u>Answer:</u> The number of moles of HI in the solution is 
moles.
<u>Explanation:</u>
We are given:
To calculate the concentration of a substance, we use the equation:
......(1)
- Concentration of ammonia:
![[NH_3]=\frac{0.405mol}{4.90L}=0.083mol/L](https://tex.z-dn.net/?f=%5BNH_3%5D%3D%5Cfrac%7B0.405mol%7D%7B4.90L%7D%3D0.083mol%2FL)
- Concentration of ammonium iodide:
![[NH_4I]=\frac{1.45mol}{4.90L}=0.30mol/L](https://tex.z-dn.net/?f=%5BNH_4I%5D%3D%5Cfrac%7B1.45mol%7D%7B4.90L%7D%3D0.30mol%2FL)
For the given chemical reaction:
The expression of 
for above equation follows:
![K_c=\frac{[HI][NH_3]}{[NH_4I]}](https://tex.z-dn.net/?f=K_c%3D%5Cfrac%7B%5BHI%5D%5BNH_3%5D%7D%7B%5BNH_4I%5D%7D)
Putting values in above equation, we get:
![7.0\times 10^{-5}=\frac{[HI]\times 0.083}{0.30}](https://tex.z-dn.net/?f=7.0%5Ctimes%2010%5E%7B-5%7D%3D%5Cfrac%7B%5BHI%5D%5Ctimes%200.083%7D%7B0.30%7D)
![[HI]=2.53\times 10^{-4}](https://tex.z-dn.net/?f=%5BHI%5D%3D2.53%5Ctimes%2010%5E%7B-4%7D)
Calculating the moles of hydrogen iodide by using equation 1, we get:
Hence, the number of moles of HI in the solution is moles.
Answer: December
Explanation:
The winter solstice is around December 21, marking the date on which the Sun is lowest in the sky at noon and rises and sets farthest south.
The half reaction with the the greater SRP has a greater tendency to gain electrons is the definition of reduction potential when considering a pair of half cell reactions.This reduction potential is measured against hydrogen electrode which is standard electrode.
If the bonds are held together tightly, as an ionic bond or even a covalent bond, there will need to be a strong force to separate those bonds. This would by why their would be a high melting point. Another reason would be re-activity. <span />
