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belka [17]
3 years ago
9

4. Which of the following have mass? Select all that apply.

Chemistry
1 answer:
valkas [14]3 years ago
4 0
All of these EXCEPT helium in a balloon
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What would happen if you play a note in a cold day on a flute?
Maurinko [17]
I don't know if this is the answer you are looking for but it would be flat unless the player pushed the tuning slide in.
7 0
3 years ago
Physical Science Structures and Properties of Matter Portfolio
daser333 [38]

Answer:

true

Explanation:

8 0
3 years ago
Chemical reaction when chromium metal is immersed in an aqueous solution of cobalt(II) chloride.
Marrrta [24]

2Cr + 3CoCl_2→ 2CrCl_3 + 3Co

Explanation:

  • The products formed are chromic chloride and cobalt.

        Chromium + Cobaltous Chloride = Chromic Chloride + Cobalt

  • Type  of reaction is Single Displacement (Substitution) which is there is a displacement of one atom.

Reactants used in the reaction are -

  • Chromium(Cr)
  • Cobaltous Chloride (CoCl_2)

Products formed in the reaction are -

  • Chromic Chloride(CrCl_3)
  • Cobalt (Co)

Hence, the chemical reaction is as follows -

  • Cr + CoCl_2 →CrCl_3 + Co

For balancing the above chemical equation we need to add a coefficient of 2 in front of chromium and of 3 in front of cobalt(II)chloride on right-hand-side while of 2 in front of chromium chloride and of 3 in front of carbon monoxide on left-hand-side of the equation.

Hence, the balanced equation is -

2Cr + 3CoCl_2→ 2CrCl_3 + 3Co

3 0
3 years ago
Determine the change in volume that takes place when a 2.00 L sample of N2 gas is heated from 250 C to 500 C.
Effectus [21]

Answer:

V₂ = 2.96 L

Explanation:

Given data:

Initial volume = 2.00 L

Initial temperature =  250°C

Final volume = ?

Final temperature = 500°C

Solution:

First of all we will convert the temperature into kelvin.

250+273 = 523 k

500+273= 773 k

According to Charles's law,

V∝ T

V = KT

V₁/T₁ = V₂/T₂

V₂ = T₂V₁/T₁

V₂ = 2 L × 773 K / 523 k

V₂ =  1546 L.K / 523 k

V₂ = 2.96 L

4 0
3 years ago
Calcular la cantidad de NaOH necesaria para preparar medio litro de disolución 2,5 N. (Dato: peso molecular del NaOH = 40 g/mol)
kolbaska11 [484]

Answer:

The amount of NaOH required to prepare a solution of 2.5N NaOH.

The molecular mass of NaOH is 40.0g/mol.

Explanation:

Since,

NaOH has only one replaceable -OH group.

So, its acidity is one.

Hence,

The molecular mass of NaOH =its equivalent mass

Normality formula can be written as:Normality=\frac{mass of solute NaOH}{its equivalent mass}  * \frac{1}{volume of solution in L} \\

Substitute the given values in this formula to get the mass of NaOH required.

2.5N=\frac{mass of NaOH}{40g/mol} *\frac{1}{1L} \\mass of NaOH=2.5N*40gmol\\                         =      100.0g

Hence, the mass of NaOH required to prepare 2.5N and 1L. solution is 100g

8 0
2 years ago
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