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Fantom [35]
2 years ago
9

The two boron atoms listed in the table are isotopes of the boron. The two carbon atoms and the two oxygen atoms are also called

isotopes. Based on the patterns in the particle compositions of these atoms, write a definition for “isotopes”
Chemistry
1 answer:
Ivan2 years ago
3 0

Answer:

A type of an atom which has a different number of neutrons but the same atomic number, therefore making it the same element. This atom would still have the same properties as well. (Ex: Vanadium-51 is an isotope of Vanadium that has 51 neutrons but still has 23 protons, as its atomic number is 23.)

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Answer:

It is the second  option.

Explanation:

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Is matter continuous and therefore has no finer structure or is it discontinuous and thus made or tiny particles
Marta_Voda [28]

Matter is discontinuous, and it is made of tiny particles called atoms

Explanation:

Matter is not a continuous structure, but it consists of tiny particles called atoms.

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7 0
2 years ago
What kind of bond would a metal and a nonmetal typically make?
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A quantity of N2 gas originally held at 5.23 atm pressure in a 1.20 −L container at 26 ∘C is transferred to a 14.5 −L container
lara31 [8.8K]

Answer:

n (N₂) =  0.256 mol

n (O₂) = 1.0848 mol

n (Total) = 1.3408 mol

Pressure in new Container =  2.222 atm

Explanation:

Data Given:

For Nitrogen gas (N₂)

Pressure of N₂ gas =  5.23 atm

Volume of N₂ gas = 1.20 L

Temperature of N₂ gas = 26° C

Temperature of N₂ gas in Kelven (K) = 26° C +273

Temperature of N₂ gas in Kelven (K) = 299K

ideal gas Constant R = 0.08206 L atm K⁻¹ mol⁻¹

quantity of gas N₂ gas = ?

For Oxygen gas (O₂)

Pressure of O₂ gas =  5.21 atm

Volume of O₂ gas = 5.21 L

Temperature of O₂ gas = 26° C

Temperature of O₂ gas in Kelven (K) = 26° C +273

Temperature of O₂ gas in Kelven (K) = 299K

ideal gas Constant R = 0.08206 L atm K⁻¹ mol⁻¹

quantity of gas O₂ gas = ?

*we also have to find the total Pressure in the new container = ?

Formula Used

                         PV =nRT

                        n (N₂) = PV /RT . . . . . . . . . . . . . (1)

* Find the quantity of N₂

Put value in formula (1)

                n (N₂) = 5.23 atm x 1.20 L / 0.08206 L atm K⁻¹ mol⁻¹ x 299K

                n (N₂) =  6.276 atm .L /  24.52 L atm. mol⁻¹ x 299K

                n (N₂) =  0.256 mol

* Find the quantity of O₂

Put value in formula (1)

                n (O₂) = 5.21 atm x 5.10 L / 0.08206 L atm K⁻¹ mol⁻¹ x 299K

                n (O₂) =  26.6 atm .L /  24.52 L atm. mol⁻¹

                n (O₂) = 1.0848 mol

*Now to find the Total Quantity of both gases

                n(Total) =  n (N₂) + n (O₂)

                 n (Total) = 0.256 mol + 1.0848 mol

                 n (Total) = 1.3408 mol

**To find the Total Pressure in the new Container

Data to calculate Total Pressure in new container

Volume of gas = 14.5 L

Temperature of gases = 20° C

Temperature of gases in Kelven (K) = 20° C +273

Temperature of gases in Kelven (K) = 293K

ideal gas Constant R = 0.08206 L atm K⁻¹ mol⁻¹

Volume Pressure in new container = ?

Formula Used

                         PV =nRT

                        P = nRT / V . . . . . . . . . . . . . (2)

Put values in Equation (2)

           P =  1.3408 mol x 0.08206 L atm K⁻¹ mol⁻¹ x 293 K / 14.5 L

           P =  2.222 atm

8 0
3 years ago
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