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Kay [80]
3 years ago
11

Rank these molecules or groups of molecules by when mammals use them as fuel, from right after a meal through only during starva

tion.
Chemistry
1 answer:
Natalka [10]3 years ago
6 0

The question is incomplete: the complete question is:

Rank molecules or group of molecules by when mammals use as fuel, starting right after meal to only through?

starvation.

a) glucose from glucose-2-phosphate from glycogen.

b) free glucose and amino acids

c) fatty acids from triglycerides

d) glucose produced from amino acids in liver.

Answer:

B

A

C

D

Explanation:

Free glucose and amino acid enters into the blood stream directly and can be used immediately after meals by mammals.

The liver stores excess glucose as glycogen, hence when glucose levels begin to reduce in the body, the pancreas releases glucagon which converts glycogen to glucose.

Triglycerides are broken down to give fatty acids which gives much more energy than glucose.

During starvation, amino acids in the liver is converted to glucose when a person goes for days without eating.

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Which of the following is a way carbon enters the atmosphere
zaharov [31]
Volcanic activity, obviously by erupting volcanoes
3 0
3 years ago
The yearly amounts of carbon emissions from cars in Belgium are normally distributed with a mean of 13.9 gigagrams per year and
zavuch27 [327]

Answer:

The correct option is;

c. 0.167

Explanation:

The parameters given are;

The mean, μ = 13.9 Gigagrams/year

The standard deviation, σ = 5.8 Gigagrams/year

The z-score formula is given as follows;

z = \dfrac{x - \mu }{\sigma }

Where:

x = Observed score = 11.5 Gigagrams/year

We have;

z = \dfrac{11.5 - 13.9 }{5.8 } =  \dfrac{-2.4 }{5.8 } = 0.4138

From the z-score table relations/computation, the probability (p-value) = 0.6605

Where:

x = Observed score = 14 Gigagrams/year

We have;

z = \dfrac{14- 13.9 }{5.8 } =  \dfrac{0.1}{5.8 } = 0.01724

From the z-score table relations/computation, the probability (p-value) = 0.4931

Therefore, the probability, p_{ca}, that the amount of carbon emissions from cars in Belgium for a randomly selected year are between 15.5 Gigagrams/year and 14 Gigagrams/year = The area under the normal curve bounded by the p-values for the two amounts of carbon emission

Which gives;

p_{ca} = 0.6605 - 0.4931 = 0.1674 ≈ 0.167

Therefore, the correct option is c. 0.167.

4 0
4 years ago
Write an equation to solve for the mass of oxygen. mass of ? = mass of ? = mass of ?
Alina [70]

Answer:

Explanation:

we know that number of moles=mass(in grams)/molar mass

for the mass of oxygen the equation becomes

mass=number of moles*molar mass

8 0
4 years ago
N2+3H2---> 2NH3
irakobra [83]
Hello!

A) H<span>ow many grams of hydrogen are necessary to react completely with 50.0g of nitrogen in the above reaction?

The balanced chemical reaction is the following one:

N</span>₂(g) + 3H₂(g) → 2NH₃(g)

To calculate the amount of hydrogen necessary we will use the following conversion factor to go from grams of nitrogen to grams of hydrogen:

50 gN_2* \frac{1 mol N_2}{28,013 g N_2}* \frac{3 moles H_2}{1 mol N_2}* \frac{2,016 g H_2}{1 mol H_2}=10,7950 g H_2

So, 10,7950 grams of H₂ are required to react with 50 g of nitrogen

<span>B) How many grams of ammonia are produced in the reaction from the previous problem?

</span>The balanced chemical reaction again is the following one:

N₂ + 3H₂ → 2NH₃

To calculate the amount of ammonia produced we will use the following conversion factor to go from grams of nitrogen to grams of ammonia:

50 gN_2* \frac{1 mol N_2}{28,013 g N_2}* \frac{2 moles NH_3}{1 mol N_2}* \frac{17,031 g NH_3}{1 mol NH_3}=60,7968 g NH_3

So, 60,7968 grams of NH₃ are produced from 50 g of nitrogen

C) <span>How many grams of silver chloride are produced from 5.0g of silver nitrate reacting with an excess of barium chloride?

The balanced chemical equation for the reaction is the following one:

2AgNO</span>₃ + BaCl₂ → 2AgCl + Ba(NO₃)₂

To calculate the mass of Silver Chloride produced we will use the following conversion factor to go from grams of Silver Nitrate to grams of Silver Chloride:

5 g AgNO_3* \frac{1 mol AgNO_3}{169,87 g AgNO_3}* \frac{2 moles AgCl}{2 moles AgNO_3}* \frac{143,32 g AgCl}{1 mol AgCl}=4,2185 g AgCl

So, 4,219 g of AgCl are produced from the reaction of 5 g of AgNO₃ 

D) <span>How much barium chloride is necessary to react with the silver nitrate in the previous problem?

</span>The balanced chemical equation for the reaction is the following one:

2AgNO₃ + BaCl₂ → 2AgCl + Ba(NO₃)₂

To calculate the mass of Barium Chloride necessary we will use the following conversion factor to go from grams of Silver Nitrate to grams of Barium Chloride:

5 g AgNO_3* \frac{1 mol AgNO_3}{169,87 g AgNO_3}* \frac{1 mol BaCl_2}{2 moles AgNO_3}* \frac{208,23 g BaCl_2}{1 mol BaCl_2}=3,08 g BaCl_2


So, 3,08 g of BaCl₂ are produced from the reaction of 5 g of AgNO₃ 

Have a nice day!
4 0
3 years ago
Autism is a disability that results from a disorder in the central nervous system. It has been speculated that the increasing nu
sasho [114]

Answer:

Explanation:

As described in the question, autism is a disability that arises from a disorder in the central nervous system <u>which is actually characterized by abnormality in the brain structure and then function</u>. Autism is known for symptoms such as challenges with communication and interaction and some obsessive behaviors. While there is generally no known scientific cause for autism but trends have suggested that vaccination in young children causes autism.

However, <u>genes could also be involved in this phenomenon because there have been reports of unusual genetic sequence in children that have autism. Hence, there is a possibility that vaccination actually triggers this genetic sequence which is then expressed as autism in the children</u>.

Please note this isn't a scientific fact and just a possibility as requested in the question.

3 0
4 years ago
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